Volume of 1 g Mole Gas at 356.2K & 1 atm: 2.92x10-2 L

[hackett5]

Homework Statement

A gas obeys the ideal-gas equation of state PV = NkT , where N = nN_A is the number of molecules in the volume V at pressure P and temperature T and n is the number of g moles of the gas.
Calculate the volume (in L) occupied by 1 g mole of the gas at atmospheric pressure and a temperature of 356.2K

1 atm = 1.013 × 10⁵ N/m2
Avogadro’s constant is 6.02214 × 10²³
k = 1.38065 × 10^-23 Nm/K.

Homework Equations

P V = N k T
= n NA * k T

The Attempt at a Solution

I tried working it, but the answer I come up with is wrong. Can someone point me in the right direction?

(1.013 x 10⁵ Nm/K)( V ) = (1 x 10^-3 kg)(1.38065x10^-23 Nm/K)(6.02214 x10²³)(356.2 K)

V = 2.92 x10^-5 m³
= 2.92 x10^-2 L

 

[hackett5]

Well, I reworked the problem and found my mistake. I got this to work out right:
(1.013x10^5)(V)=(356.2)(6.02214x10^23)(1.38065x10^-23)
V=.029236 m^3
V=29.236 L