- #1

- 8

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[tex]\int_{0}^{2\pi}\int_{0}^{h}\int_{0}^{R}\rho d\rho dz d\phi[/tex]

...but I think that this is setting up the integral for a cylinder and not a cone. Any suggestions so I end up with the correct volume?

[tex]V_{cone} = \frac{1}{3}\pi r^2 h[/tex]

Thank you!