Volume of a cube as a function of surface area

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The volume of a cube can be expressed as a function of its total surface area using the equations for surface area (SA = 6x^2) and volume (V = x^3). To find the volume in terms of surface area, x can be isolated from the surface area equation, resulting in x = sqrt(SA/6). Substituting this expression for x into the volume equation yields V = (SA/6)^(3/2). The final formula for the volume in terms of surface area is V = (SA^(3/2))/(6√6).
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Homework Statement



Express the volume of a cube as a fuction of the total surface area

Homework Equations



Surface area = 6x^2
Volume = x^3

The Attempt at a Solution



So, we need to manipulate the surface area equation so we can use it to find volume right?


SA = 6x^2
sqrt(SA/6) = x
or (SA/6)^(1/2) = x

and sub it in the Volume equation

(SA/6)^(1/2)*3

so we would have (SA/6^3)^3/2

Is this correct answer to the question?
please help
 
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lovemake1 said:

Homework Statement



Express the volume of a cube as a fuction of the total surface area

Homework Equations



Surface area = 6x^2
Volume = x^3

The Attempt at a Solution



So, we need to manipulate the surface area equation so we can use it to find volume right?


SA = 6x^2
sqrt(SA/6) = x
or (SA/6)^(1/2) = x

and sub it in the Volume equation

(SA/6)^(1/2)*3
You should actually have an equation. Let's call S the surface area.
V = x3 = (S/6)3/2
or
V = (\frac{S}{6})^{3/2}
You can also write this as \frac{S^{3/2}}{6^{3/2}} = \frac{S^{3/2}}{6\sqrt{6}}
lovemake1 said:
so we would have (SA/6^3)^3/2
No, you have too many factors of 6 in the denominator.
lovemake1 said:
Is this correct answer to the question?
please help
 

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