Volume of a Solid by Revolution

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SUMMARY

The discussion centers on calculating the volume of a solid obtained by rotating the region bounded by the line equation y=8x+32 and the x-axis about the y-axis. The correct approach involves integrating with respect to y, using the formula for volume V = π∫[f(x)]² dy. The participants confirm that the volume should be calculated as (4096/3)π, approximately 4289.32, indicating that the initial answer of 512/3π is incorrect. The discrepancy with online resources suggests potential issues with the reference material rather than the participants' calculations.

PREREQUISITES
  • Understanding of calculus, specifically integration techniques.
  • Familiarity with the method of solids of revolution.
  • Knowledge of the volume formula for cones: V = (1/3)πr²h.
  • Experience with graphing linear equations and interpreting their geometric implications.
NEXT STEPS
  • Study the method of solids of revolution in detail.
  • Practice calculating volumes using the disk and washer methods.
  • Explore the implications of significant figures in mathematical calculations.
  • Review the properties of linear equations and their graphical representations.
USEFUL FOR

Students and educators in calculus, particularly those focusing on integration and geometric applications, as well as anyone seeking to clarify concepts related to volume calculations of solids of revolution.

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Homework Statement


Hi, the next problem I thought it was easy...and I really think it is, but I haven't come with the right answer :S. I compare the answer in an internet page of problems and all it says is "wrong"...

The problem is the following:
Find the volume of the solid obtained by rotating the region bounded by
y=8*x+32, y=0 about the y-axis.

Homework Equations


I made the sketh in Maple:
http://img109.imageshack.us/img109/5669/solidvolumexi5.th.jpg

The Attempt at a Solution


Then I solve for x:

x=(y/8)-4
and wrote the Integral with respect to y, and limits from 0 to 32 (where the function y=8x+32 intersects the y-axis).
Integral of Pi*f(x)^2, from y=0 to y=32, it should give me the volume, isn't it?

http://img164.imageshack.us/img164/98/equationie6.th.jpg
My answer: 512/3 * Pi= 536.1651462

But the internet page says I'm wrong but I don't know why :S

Any help is welcome, Thanks in advance!
 
Last edited by a moderator:
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Your answer looks right. I'd say the super trustworthy internet is wrong ;). (Disclaimer: I'm getting back into calc after a year of none, but still I'm quite sure you're correct).
 
Possibly: Integration of Pi * (8x + 32)^2. -4 (lower limit) and 0 (upper limit)
 
Last edited:
Thanks to all of you for your answers.

AngeloG, I already tried what you suggest and I came with the answer:
4289.321169 which is wrong as well.

And because the region should be rotated about the Y-Axis and not about the X-axis, that's why I solved the equation for X, in order to have only Y's so I could integrate with respect to dy, then my limits are Y=0 and Y=32.

I hope I didn't understand you another thing, maybe "4289.321169" wasn't what you get, so I would like to know your answer.

Thx again^^, cheers!
 
Err, forgot to say change the x's for y's and the y's for x's.

8x + 32 is basically the same as 8y + 32. One is just tilted on it's side, which is the y. Then you can integrate from -4 to 0, then rotate it around y-axis tilted.

(4096 / 3) * Pi, which is ~4289.3

However, I am wrong =). I was just doing the other half, considering your half was wrong. There's only two ways to do this and if both provide the wrong answer. Might be the page.
 
Last edited:
y= 8x+ 32 is a straight line with intercepts (0, 32) and (-4,0), rotating around the y-axis gives a cone with height 32 and radius 4. you can check the volume by using the standard formula for volume of a cone: V= \frac{1}{3}\pi r^2h.
 
Thx again for all your answers^^, I didnt know there will be so many options or ways to solve the problem.

AngeloG, thanks for your reply.
HallsofIvy, I tried that :O, and I got: 536.1651462, but the page says its wrong -.-, so now I'm almost sure that is the webpage.

cheers!
 
It might be a significant digits problem. Did you try just "536"?
 

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