Volume of revolution, region bounded by two functions

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SUMMARY

The discussion focuses on calculating the volume of revolution for the area R bounded by the curves \(y^2 + x^2 = 5\), \(y = 2x\), and the y-axis (x = 0) in the first quadrant. The user proposes using the cylindrical shell method and presents the integral \( \int_0^1 x(\sqrt{5 - x^2} - 2x) \cdot 2\pi \, dx \) to find the volume T when R is rotated around the Y-axis. The integral formulation is confirmed as correct for this specific problem.

PREREQUISITES
  • Understanding of volume of revolution concepts
  • Familiarity with the cylindrical shell method
  • Knowledge of integration techniques
  • Basic understanding of Cartesian coordinates and curves
NEXT STEPS
  • Study the cylindrical shell method in detail
  • Practice calculating volumes of revolution using different methods
  • Explore the implications of rotating regions around different axes
  • Review integration techniques for solving definite integrals
USEFUL FOR

Students in calculus courses, educators teaching volume of revolution concepts, and anyone interested in applying integration techniques to geometric problems.

Kqwert
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Homework Statement


Let R be the area in the xy-plane in the 1st quadrant which is bounded by the curves y^2+x^2 = 5, y = 2x and x = 0. (y-axis). Let T be the volume of revolution that appears when R is rotated around the Y axis. Find the volume of T.

Homework Equations

The Attempt at a Solution


This is the integral I have put up, using the cylindrical shell method:

int(x*(sqrt(5-x^2)-2x)*2pi)dx from 0 to 1. Is this the correct integral?
 
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Looks right to me.
 

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