Volume of Rotated Region Using Cylindrical Shells - Step-by-Step Guide

Click For Summary
SUMMARY

The discussion focuses on calculating the volume of a region bounded by the curves y = (x - 1)^(1/2), y = 0, and x = 5 when rotated about the line y = 3 using the method of cylindrical shells. The correct setup for the integral is identified as the integral from 0 to 2 of 2π(3 - (y^2 + 1))(y) dy, which yields a volume of 24π. Participants clarify the geometry of the cylindrical shell, emphasizing the importance of understanding the radius and dimensions of the shells formed during rotation.

PREREQUISITES
  • Understanding of the method of cylindrical shells
  • Familiarity with integral calculus
  • Knowledge of curve equations and their graphical representations
  • Ability to set up and evaluate definite integrals
NEXT STEPS
  • Study the method of cylindrical shells in detail
  • Learn how to derive volume integrals for different shapes
  • Explore the concept of cross-sections in solid geometry
  • Practice setting up integrals for various rotation axes
USEFUL FOR

Students and educators in calculus, particularly those focusing on volume calculations and solid geometry, as well as anyone seeking to master the method of cylindrical shells for solving volume problems.

shaneewert
Messages
2
Reaction score
0
Please help! How do I do this problem?

Using the method of cylindrical shells, find the volume generated by rotating the region the region bounded by the given curves about the specified axis.

y=(x-1)^(1/2), y=0, x=5; about y = 3

Please tell me how to set up the integral! Any help is MUCH appreciated.

So far I have Integral from 0 to 2 of (3-(y^2+1))*y dy I know that isn't right, because I am not getting the right answer! The book says that it is 24pi.

Thank you.
 
Physics news on Phys.org
Do you know what each shell looks like?

The cross section of each shell is a long, narrow, flat rectangle, whose long dimension is parallel to the x-axis and stretches from the point where x = y^2 + 1 to the point where x = 5. It is parametrized by y. The shell itself is that rectangle rotated around the line y = 3. Ignore the small vertical width of the rectangle for a minute (which is dy) so that the shell is just like a horizontal tube with no thickness. What is the area of the outer surface of this tube? It has a radius--the radius is 3 - (y^2 + 1). So what is its circumference? What is its length?
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
3
Views
2K
Replies
4
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K