Centroid of solid enclosed by surface z= y^2 , plane x=0 ,

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SUMMARY

The discussion focuses on finding the centroid of a solid enclosed by the surface defined by the equation z = y², the plane x = 0, the plane x = 1, and the plane z = 1, with a uniform density of 1. The centroid is calculated using the formula for mass of inertia divided by mass. Participants emphasize the importance of accurately visualizing the solid, correcting misconceptions about the geometry involved, and clarifying the use of polar coordinates in this context.

PREREQUISITES
  • Understanding of centroid calculations in three-dimensional geometry
  • Familiarity with the equations of surfaces and planes
  • Knowledge of mass of inertia and its application in centroid determination
  • Basic skills in visualizing geometric shapes in 3D space
NEXT STEPS
  • Study the derivation of centroid formulas for solids of revolution
  • Learn about the application of polar coordinates in three-dimensional integrals
  • Explore the concept of mass of inertia in relation to centroid calculations
  • Review techniques for accurately sketching three-dimensional solids
USEFUL FOR

Students in engineering or physics courses, educators teaching solid geometry, and anyone involved in mechanical design or structural analysis who needs to calculate centroids of complex shapes.

chetzread
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Homework Statement


Find the centroid of solid enclosed by surface z= y^2 , plane x=0 , x = 1 and z =1 . The density is 1

Homework Equations

The Attempt at a Solution


Here's my working .

Centoird = mass of inertia / mass
So , i find the mass first .

It's clear that the circle is on zx plane ... I am not sure whether to use z= rcos theta or z = rsin theta . Can you help ?
 

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chetzread said:

Homework Statement


Find the centroid of solid enclosed by surface z= y^2 , plane x=0 , x = 1 and z =1 . The density is 1

Homework Equations

The Attempt at a Solution


Here's my working .

Centoird = mass of inertia / mass
So , i find the mass first .

It's clear that the circle is on zx plane ... I am not sure whether to use z= rcos theta or z = rsin theta . Can you help ?
Almost everything you have here is wrong.
  • Your drawing is way off. Take more time and get a more careful drawing the represents the solid described in your problem statement.
  • "the circle is on zx plane" -- No, it's not a circle.
  • You are apparently trying to use polar coordinates -- why?
 

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