Volume using Compressibility Factor

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To find the volume of 2 kg of ethylene at 270 K and 2500 kPa using the compressibility factor (Z), the equation PV = ZnRT is applied. The values for reduced temperature (Tr) and reduced pressure (Pr) are calculated, yielding Z as approximately 0.75. The user is confused about the units for pressure and the number of moles (n), with an initial calculation of n as 71.43 mol based on the molecular weight of ethylene. It is suggested to use the mass in kilograms with the appropriate gas constant for calculations, and to ensure unit consistency, particularly with pressure. Corrections in the approach are necessary to achieve accurate volume results.
MechE2015
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Homework Statement



Find the volume of 2 kg of ethylene at 270 K, 2500 kPa using Z

Homework Equations



Method to Solve for Z, Using Tr and Pr

PV = ZnRT

The Attempt at a Solution



Tr = 0.9561
Pr = 0.496
Z found to be approx. 0.75
R given on a table at 0.2964 kJ/kg K

From here, I should have all information needed, I was just confused on units at this point.
V = ZnRT/P
V = (0.75)*(n)*(0.2964 kJ/kg K)*(270 K) / (2500 kPa)

At this point, my main questions are (probably very simple):

What is n, and why? My best guess: (2000 g)/(28 g/mol) = 71.43 mol

What are units for P? My best guess: atm, -> 2500 kPa*24.67 atm/kPa = 61675 atm

Using these numbers, I get Volume to be way too low, corrections needed somewhere. Help appreciated.
 
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MechE2015 said:

Homework Statement



Find the volume of 2 kg of ethylene at 270 K, 2500 kPa using Z

Homework Equations



Method to Solve for Z, Using Tr and Pr

PV = ZnRT

The Attempt at a Solution



Tr = 0.9561
Pr = 0.496
Z found to be approx. 0.75
R given on a table at 0.2964 kJ/kg K

From here, I should have all information needed, I was just confused on units at this point.
V = ZnRT/P
V = (0.75)*(n)*(0.2964 kJ/kg K)*(270 K) / (2500 kPa)

At this point, my main questions are (probably very simple):

What is n, and why? My best guess: (2000 g)/(28 g/mol) = 71.43 mol

What are units for P? My best guess: atm, -> 2500 kPa*24.67 atm/kPa = 61675 atm

Using these numbers, I get Volume to be way too low, corrections needed somewhere. Help appreciated.

Take a look at your units. If you're using kj/kg K for R, you should use equation:
PV = mRT, where R is the gas constant for that gas and m is the mass in kilograms. If you use PV = nRuT (Where Ru is the universal gas constant), then you'll need to use the number of moles.

Also, use the fact that 1 Pa*m^3 = 1 J.
 

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