Volume using Compressibility Factor

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SUMMARY

The discussion focuses on calculating the volume of 2 kg of ethylene at 270 K and 2500 kPa using the compressibility factor (Z). The user determined Tr as 0.9561 and Pr as 0.496, resulting in Z being approximately 0.75. The equation PV = ZnRT was utilized, but confusion arose regarding the number of moles (n) and the pressure units. Clarifications were provided, emphasizing the need to use the appropriate gas constant R based on the mass in kilograms for accurate volume calculations.

PREREQUISITES
  • Understanding of the Ideal Gas Law and its applications
  • Familiarity with compressibility factor (Z) calculations
  • Knowledge of thermodynamic properties such as temperature (T) and pressure (P)
  • Basic unit conversions, particularly between kPa and atm
NEXT STEPS
  • Study the Ideal Gas Law and its limitations in real gas scenarios
  • Learn about the compressibility factor and its significance in gas calculations
  • Explore the relationship between pressure, volume, and temperature in thermodynamics
  • Review unit conversion techniques, especially for pressure and volume
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Students in chemistry or engineering fields, particularly those studying thermodynamics and gas behavior, as well as professionals involved in chemical process design and analysis.

MechE2015
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Homework Statement



Find the volume of 2 kg of ethylene at 270 K, 2500 kPa using Z

Homework Equations



Method to Solve for Z, Using Tr and Pr

PV = ZnRT

The Attempt at a Solution



Tr = 0.9561
Pr = 0.496
Z found to be approx. 0.75
R given on a table at 0.2964 kJ/kg K

From here, I should have all information needed, I was just confused on units at this point.
V = ZnRT/P
V = (0.75)*(n)*(0.2964 kJ/kg K)*(270 K) / (2500 kPa)

At this point, my main questions are (probably very simple):

What is n, and why? My best guess: (2000 g)/(28 g/mol) = 71.43 mol

What are units for P? My best guess: atm, -> 2500 kPa*24.67 atm/kPa = 61675 atm

Using these numbers, I get Volume to be way too low, corrections needed somewhere. Help appreciated.
 
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MechE2015 said:

Homework Statement



Find the volume of 2 kg of ethylene at 270 K, 2500 kPa using Z

Homework Equations



Method to Solve for Z, Using Tr and Pr

PV = ZnRT

The Attempt at a Solution



Tr = 0.9561
Pr = 0.496
Z found to be approx. 0.75
R given on a table at 0.2964 kJ/kg K

From here, I should have all information needed, I was just confused on units at this point.
V = ZnRT/P
V = (0.75)*(n)*(0.2964 kJ/kg K)*(270 K) / (2500 kPa)

At this point, my main questions are (probably very simple):

What is n, and why? My best guess: (2000 g)/(28 g/mol) = 71.43 mol

What are units for P? My best guess: atm, -> 2500 kPa*24.67 atm/kPa = 61675 atm

Using these numbers, I get Volume to be way too low, corrections needed somewhere. Help appreciated.

Take a look at your units. If you're using kj/kg K for R, you should use equation:
PV = mRT, where R is the gas constant for that gas and m is the mass in kilograms. If you use PV = nRuT (Where Ru is the universal gas constant), then you'll need to use the number of moles.

Also, use the fact that 1 Pa*m^3 = 1 J.
 

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