W Boson Vertices: Incoming vs Outgoing

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The discussion centers on the transformation of W boson vertices from incoming to outgoing particles within the context of field theory. Specifically, it addresses the W boson interactions involving the CKM matrix element Vud and its complex conjugate Vud^*. The conversation clarifies that the W^{-}u\bar{d} term can represent both decay (W^{+}\rightarrow u\bar{d}) and annihilation (d\bar{u}\rightarrow W^{-}) processes, which share the same coupling phase. It emphasizes that the conjugate processes arise from the Hermitian conjugate term in the Lagrangian, leading to opposite phases in interactions.

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kaksmet
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Hi,

a simple question on W boson vertices (and I guess field theory in general). If I have a W boson vertex for incoming particles, i.e.

W^+ ubar d and W^- u dbar

how do I change this for outgoing W's. The first interaction contains a CKM matrix element Vud and the second a Vud^*, and I want to figure out which one of them has the complex conjugate in the case of outgoing W's.

Thanks!
 
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First of all remember that an interaction vertex in the lagrangian can represent several different processes in feynman diagrams.

the W^{-}u\bar{d} term in the lagrangian can be the decay W^{+}\rightarrow u\bar{d} or the annhilation d\bar{u}\rightarrow W^{-} , both with the same coupling (including the same phase)

the conjugate decay and annihilation processes will come from the hermitian conjugate term in the lagrangian, and they will have opposite phase.

A useful way to remember which processes will have the same phase and which will not is to remember that the CPT inversed process has the same coupling (including the same phase).
In our case W^{+}\rightarrow u\bar{d} is the CPT inversed process of d\bar{u}\rightarrow W^{-} , since each particle is replaced by its antiparticle and the time direction is reversed.
 

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