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What is the physics explanation of it? Is it because you try to deflect momentum or inertia? What is the right description to explain it?

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- Thread starter Cobul
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In summary, a wall made of a pendulum or a ball attached to a string on top will not attract seismic forces, whereas a wall fixed solid will. If the wall is more flexible, it can deflect seismic forces.

- #1

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What is the physics explanation of it? Is it because you try to deflect momentum or inertia? What is the right description to explain it?

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- #2

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That is not a meaningful word in that context.

Do you perhaps mean "susceptible to"?

Any would structure affixed to the ground,such as a wall, will be more susceptible to seismic tremors than something mechanically buffered, such as a pendulum, but pendulums don't make efficient walls.

I think you should elaborate on your question.

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What? Is "pendulum" a new element I've never heard of? What does a "wall made of pendulum" look like? And how do I insulate it?Cobul said:If your house wall is made of pendulum or a ball attached to a string on top. It won't attract seismic forces. Whereas if the wall is fixed solid. It can attract seismic forces.

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In general, it's not so much about attracting vs. deflecting. It's more about dissipating the energy over shorter vs. longer time. Flexible structures store the energy and dissipate it over longer time, so the peak forces are smaller. In the case of oscillation you also need to avoid resonance with the driving frequency, so you need the right amount of stiffness vs damping.Cobul said:It won't attract much seismic force that when it is rigid. I just want to know how it deflects the energy.

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There is some impedance mismatch between a flexible building and a rigid earth. There is an even greater mismatch between roller bearings and a rigid earth.

- #8

Just taking your question at face value, I think it could be kind of interesting! Except I guess when you say "attracting [susceptible to?] seismic forces" it's more instead more meaningful to ask whether the structure would be subject to greater stress.

First, model the wall as either a vertical beam or a vertical plate. If the ground is subject to an acceleration ##\mathbf{A} = A_0 \cos{(\omega_d t)} \mathbf{e}_x## then you can model the situation by subjecting the structure to a uniform body force ##\mathbf{f} = - \rho A_0 \cos{(\omega_d t)} \mathbf{e}_x##. Taking the beam model as an example, this is equivalent to the problem of a horizontal cantilever beam, fixed at one end, and subject to a time-dependent gravitational potential ##U(y) = - \mathbf{f} \cdot \mathbf{x} = y \rho A_0 \cos{(\omega_d t)}##. Then you can just take the EL equation for the beam (assuming homogeneity of E and I)$$EI \frac{\partial^4 w}{\partial x^4} + \mu \frac{\partial^2 w}{\partial t^2} = q$$solve for ##w(x,t)## and from that determine the components ##\sigma_{ik}## of the stress tensor in the beam. Might be fun to try varying some of the parameters to see whether a flexible beam or a rigid beam will experience greater stress. [Maybe easier said than done, but hey, Mathematica exists for a reason!]

First, model the wall as either a vertical beam or a vertical plate. If the ground is subject to an acceleration ##\mathbf{A} = A_0 \cos{(\omega_d t)} \mathbf{e}_x## then you can model the situation by subjecting the structure to a uniform body force ##\mathbf{f} = - \rho A_0 \cos{(\omega_d t)} \mathbf{e}_x##. Taking the beam model as an example, this is equivalent to the problem of a horizontal cantilever beam, fixed at one end, and subject to a time-dependent gravitational potential ##U(y) = - \mathbf{f} \cdot \mathbf{x} = y \rho A_0 \cos{(\omega_d t)}##. Then you can just take the EL equation for the beam (assuming homogeneity of E and I)$$EI \frac{\partial^4 w}{\partial x^4} + \mu \frac{\partial^2 w}{\partial t^2} = q$$solve for ##w(x,t)## and from that determine the components ##\sigma_{ik}## of the stress tensor in the beam. Might be fun to try varying some of the parameters to see whether a flexible beam or a rigid beam will experience greater stress. [Maybe easier said than done, but hey, Mathematica exists for a reason!]

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