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Physics
Classical Physics
Electromagnetism
Water bending with comb: but where do the electrons go?
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[QUOTE="sophiecentaur, post: 6438457, member: 199289"] (This is about the original 'comb' topic) There must be two things at work. For individual drops, any charge that they could get will be small, especially if they form at the tap (far from the comb) and the polarisation within the drop will produce less net force on the way past the comb. A continuous stream goes close to the comb and the 'polarisation' can involve 'the other' charges moving all the way to earth. Also, the experiment would look different if very pure water were used because it would only work by polarisation. This can probably be regarded as a difference in capacitance, which is much higher between the comb and a stream than between the comb and a drop. The post you are querying refers to the Kelvin Dropper, which (the name suggests it) works on individual drops. True; you are right and I now see it was false. The 'polarisation' takes place in the top tank. You could use the mains water supply too and the mean potential would be zero. And then the GPE from the falling charged drops allows a large increase in Electric Potential across the + and - structures because the two rings have increasingly high (magnitude) potentials. I think the dimensions of the apparatus need to be about right for the best results. The field between the dropper and the rings needs to be high so that the charge that's shifted per drop is high enough to carry a useful current into the buckets. [/QUOTE]
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Classical Physics
Electromagnetism
Water bending with comb: but where do the electrons go?
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