Wave dispersion and the bandwidth theorem

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SUMMARY

The discussion focuses on the application of the bandwidth theorem to a propagating wave packet with an initial length L0. The minimum range of angular frequencies present in the wave packet is defined by the equation Δω = vg/L0, where vg represents the group velocity. A participant noted an alternative expression, Δω = 2π(vg/L0), and sought clarification on the bandwidth theorem's derivation, specifically the relationship ΔkΔx ≈ 2π. The consensus confirms the validity of both expressions derived from the dispersion relationship ω² = gk.

PREREQUISITES
  • Understanding of wave packets and their properties
  • Familiarity with the concept of group velocity (vg)
  • Knowledge of the dispersion relationship (ω² = gk)
  • Basic grasp of the bandwidth theorem and its mathematical implications
NEXT STEPS
  • Study the derivation of the bandwidth theorem in detail
  • Explore the implications of group velocity in wave mechanics
  • Learn about the dispersion relationship for different types of waves
  • Investigate practical applications of wave packets in physics
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Students and educators in physics, particularly those focusing on wave mechanics, as well as researchers interested in the mathematical foundations of wave propagation and dispersion.

RYANDTRAVERS
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Homework Statement


Consider a propagating wave packet with initial length L0.
Use the bandwidth theorem to show that the minimum range of angular frequencies present in the wave packet is approximately:
\begin{equation}
\Delta \omega = \frac{v_{g}}{L_{0}}
\end{equation}
where vg is the group velocity.

Homework Equations


The dispersion relationship for the wave is:
\begin{equation}
\omega ^{2} = gk
\end{equation}

The Attempt at a Solution


attached as photo along with original problem sheet. For some reason I get the answer as:
\begin{equation}
\Delta \omega = 2\pi \frac{v_{g}}{L_{0}}
\end{equation}
see method attached.
 

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Last edited:
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Yes i agree with your result. but how exactly have you been taught the bandwidth theorem? I just know it as \Delta k\Delta x\approx 2\pi where \Delta k , \Delta x are defined properly.
 
Last edited:
Well, yeah we defined it as \begin{equation} \Delta k \Delta x = 2\pi \end{equation} and then the rest can be derived from there.
 

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