Wave equation, D'Alembert's Solution

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Tuneman
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I am having trouble understanding the solution to the wave equation:

Formula for u(x,t): one half of g(x-ct) plus g(x+ct), plus one over 2c times the integral of h(xi) from x-ct to x+ct, d xi.


this is thought of as the final solution to the PDE:
Wave equation: second partial derivative of u with respect to x equals (1/c^2) times the second partial derivative of u with respect to t.


but I see that:
Mathematical expression sin(x - ct) + sin(x + ct), a sum of two sine terms with arguments x minus ct and x plus ct.


is a solution to the function. But what I don't get is why D'Alembert's Solution isn't in terms of sines and cosines like that solution right above.

Is it because D'Albemerts is a gereneral solution, and the other is a specific solution? If so, still how come the general solution to the problem isn't expressed as a wave, and instead of some arbitrary function g(x-ct)?
 
The general solution is a wave. But a wave is not necessarily periodic like sine or cosine. Imagine a taut rope that is distorted initially in a shape that consists of a bulge, say a triangle between x= -1 and x= 1, given by y= x+1 for x<0, y= 1-x for x>=0 and then released from rest at t=0. "g" splits into two parts which move right and left: that's what (1/2)g(x-ct) and (1/2)g(x+ct) are. The h integral allows non-zero speed at t= 0 also.