Wave equation, taut string hit with hammer

Click For Summary
The discussion revolves around solving the wave equation for a string fixed at both ends, struck by a hammer of width 'a' in the middle. The initial conditions specify that the string is at rest initially, except for the region where it is struck, which has a defined velocity 'v0'. Participants address issues with the Fourier series coefficients, particularly the limits of integration and the correct representation of the initial velocity condition. There is a clarification regarding the speed parameter 'c', which is confirmed to be equivalent to 'v'. Overall, the conversation focuses on refining the mathematical approach to accurately model the wave behavior resulting from the hammer strike.
Taylor_1989
Messages
400
Reaction score
14

Homework Statement


A string of length L is fixed at both ends ##u(0,L)=u(L,t)=0## The string is struck in the middle with a hammer of width a, leading to an intial condtion ##u(x,0)=0## and

$$U_t(x,0)=v_0 $$ for $$\frac{l}{2}-\frac{a}{2} \leq x \leq \frac{l}{2}+\frac{a}{2} $$

and

$$U_t(x,0)=0 $$ other wise

I have printed screen in the question Just encase it make no sense what I have wirtten

upload_2017-12-10_16-21-12.png


I am not going to put full working, I am having trouble with one particular part the intial condtions for my Fourier series.

Homework Equations


$$U_t(x,0)=\sum_{n=1}^\infty \left(-\frac{n\pi c}{L}\right)B_n sin(\frac{n\pi}{L}x)$$ [1]

$$\left(-\frac{n\pi c}{L}\right)B_n=\frac{2}{l}\int _0^lv_0sin\left(\frac{n\pi }{L}x\right)dx\:$$ [2]

$$B_n=-\frac{2v_0}{-n\pi c}\int _{\left(\frac{L}{2}-\frac{a}{2}\right)}^{\frac{L}{2}+\frac{a}{2}}sin\left(\frac{n\pi }{L}x\right)dx\:$$ [3]

The Attempt at a Solution



[3] soultuion
$$B_n=\frac{2Lv_0}{n^2\pi ^2c}\left(cos\left(\frac{n\pi }{2}\left(\frac{L+a}{L}\right)-cos\left(\frac{n\pi }{2}\left(\frac{L-a}{L}\right)\right)\right)\right)$$

I believe I have gone wrong with the limits and my problem lies in how the size of the hammer is effecting the wave in this case, could someone please advise, thanks in advace
 

Attachments

  • upload_2017-12-10_16-21-12.png
    upload_2017-12-10_16-21-12.png
    27 KB · Views: 1,242
Physics news on Phys.org
Taylor_1989 said:

Homework Statement


A string of length L is fixed at both ends ##u(0,L)=u(L,t)=0## The string is struck in the middle with a hammer of width a, leading to an intial condtion ##u(x,0)=0## and

$$U_t(x,0)=v_0 $$ for $$\frac{l}{2}-\frac{a}{2} \leq x \leq \frac{l}{2}+\frac{a}{2} $$

and

$$U_t(x,0)=0 $$ other wise

I have printed screen in the question Just encase it make no sense what I have wirtten

View attachment 216437

I am not going to put full working, I am having trouble with one particular part the intial condtions for my Fourier series.

Homework Equations


$$U_t(x,0)=\sum_{n=1}^\infty \left(-\frac{n\pi c}{L}\right)B_n sin(\frac{n\pi}{L}x)$$ [1]

$$\left(-\frac{n\pi c}{L}\right)B_n=\frac{2}{l}\int _0^lv_0sin\left(\frac{n\pi }{L}x\right)dx\:$$ [2]

$$B_n=-\frac{2v_0}{-n\pi c}\int _{\left(\frac{L}{2}-\frac{a}{2}\right)}^{\frac{L}{2}+\frac{a}{2}}sin\left(\frac{n\pi }{L}x\right)dx\:$$ [3]

The Attempt at a Solution



[3] soultuion
$$B_n=\frac{2Lv_0}{n^2\pi ^2c}\left(cos\left(\frac{n\pi }{2}\left(\frac{L+a}{L}\right)-cos\left(\frac{n\pi }{2}\left(\frac{L-a}{L}\right)\right)\right)\right)$$

I believe I have gone wrong with the limits and my problem lies in how the size of the hammer is effecting the wave in this case, could someone please advise, thanks in advace

The wave equation has a speed parameter "##v##" in it; why does your solution have no ##v## anywhere? Is your ##c## perhaps equal to the ##v## in the question?
 
Sorry yes my c=v my appolgise. I have also just had a throught could I use the indenties for cos(a+b) and cos(a-b) to solve this problem
 
Last edited:
Taylor_1989 said:
I am not going to put full working, I am having trouble with one particular part the intial condtions for my Fourier series.

Homework Equations


$$U_t(x,0)=\sum_{n=1}^\infty \left(-\frac{n\pi c}{L}\right)B_n sin(\frac{n\pi}{L}x)$$ [1]

I agree up to here except I don't have a minus sign. But that shouldn't affect the final answer.

$$\left(-\frac{n\pi c}{L}\right)B_n=\frac{2}{l}\int _0^l v_0 \sin\left(\frac{n\pi }{L}x\right)dx$$
That isn't quite right. Apparently the ##l## should be ##L##, but the function isn't ##v_0## on that interval. So it is better written$$
\left(-\frac{n\pi c}{L}\right)B_n=\frac{2}{L}\int _0^L u_t(x,0) \sin\left(\frac{n\pi }{L}x\right)dx$$ $$
\left(-\frac{n\pi c}{L}\right)B_n=\frac{2}{L}\int _{\frac L 2 - \frac a 2}
^{\frac L 2 + \frac a 2 }v_0 \sin\left(\frac{n\pi }{L}x\right)dx$$

$$B_n=-\frac{2v_0}{-n\pi c}\int _{\left(\frac{L}{2}-\frac{a}{2}\right)}^{\frac{L}{2}+\frac{a}{2}}sin\left(\frac{n\pi }{L}x\right)dx\:$$ [3]

The Attempt at a Solution



[3] soultuion
$$B_n=\frac{2Lv_0}{n^2\pi ^2c}\left(cos\left(\frac{n\pi }{2}\left(\frac{L+a}{L}\right)-cos\left(\frac{n\pi }{2}\left(\frac{L-a}{L}\right)\right)\right)\right)$$

I believe I have gone wrong with the limits and my problem lies in how the size of the hammer is effecting the wave in this case, could someone please advise, thanks in advace

I didn't check your final answer but I don't see any obvious major errors.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 105 ·
4
Replies
105
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K
Replies
4
Views
2K