Wave equation, taut string hit with hammer

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Taylor_1989
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Homework Statement


A string of length L is fixed at both ends ##u(0,L)=u(L,t)=0## The string is struck in the middle with a hammer of width a, leading to an intial condtion ##u(x,0)=0## and

$$U_t(x,0)=v_0 $$ for $$\frac{l}{2}-\frac{a}{2} \leq x \leq \frac{l}{2}+\frac{a}{2} $$

and

$$U_t(x,0)=0 $$ other wise

I have printed screen in the question Just encase it make no sense what I have wirtten

upload_2017-12-10_16-21-12.png


I am not going to put full working, I am having trouble with one particular part the intial condtions for my Fourier series.

Homework Equations


$$U_t(x,0)=\sum_{n=1}^\infty \left(-\frac{n\pi c}{L}\right)B_n sin(\frac{n\pi}{L}x)$$ [1]

$$\left(-\frac{n\pi c}{L}\right)B_n=\frac{2}{l}\int _0^lv_0sin\left(\frac{n\pi }{L}x\right)dx\:$$ [2]

$$B_n=-\frac{2v_0}{-n\pi c}\int _{\left(\frac{L}{2}-\frac{a}{2}\right)}^{\frac{L}{2}+\frac{a}{2}}sin\left(\frac{n\pi }{L}x\right)dx\:$$ [3]

The Attempt at a Solution



[3] soultuion
$$B_n=\frac{2Lv_0}{n^2\pi ^2c}\left(cos\left(\frac{n\pi }{2}\left(\frac{L+a}{L}\right)-cos\left(\frac{n\pi }{2}\left(\frac{L-a}{L}\right)\right)\right)\right)$$

I believe I have gone wrong with the limits and my problem lies in how the size of the hammer is effecting the wave in this case, could someone please advise, thanks in advace
 

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Taylor_1989 said:

Homework Statement


A string of length L is fixed at both ends ##u(0,L)=u(L,t)=0## The string is struck in the middle with a hammer of width a, leading to an intial condtion ##u(x,0)=0## and

$$U_t(x,0)=v_0 $$ for $$\frac{l}{2}-\frac{a}{2} \leq x \leq \frac{l}{2}+\frac{a}{2} $$

and

$$U_t(x,0)=0 $$ other wise

I have printed screen in the question Just encase it make no sense what I have wirtten

View attachment 216437

I am not going to put full working, I am having trouble with one particular part the intial condtions for my Fourier series.

Homework Equations


$$U_t(x,0)=\sum_{n=1}^\infty \left(-\frac{n\pi c}{L}\right)B_n sin(\frac{n\pi}{L}x)$$ [1]

$$\left(-\frac{n\pi c}{L}\right)B_n=\frac{2}{l}\int _0^lv_0sin\left(\frac{n\pi }{L}x\right)dx\:$$ [2]

$$B_n=-\frac{2v_0}{-n\pi c}\int _{\left(\frac{L}{2}-\frac{a}{2}\right)}^{\frac{L}{2}+\frac{a}{2}}sin\left(\frac{n\pi }{L}x\right)dx\:$$ [3]

The Attempt at a Solution



[3] soultuion
$$B_n=\frac{2Lv_0}{n^2\pi ^2c}\left(cos\left(\frac{n\pi }{2}\left(\frac{L+a}{L}\right)-cos\left(\frac{n\pi }{2}\left(\frac{L-a}{L}\right)\right)\right)\right)$$

I believe I have gone wrong with the limits and my problem lies in how the size of the hammer is effecting the wave in this case, could someone please advise, thanks in advace

The wave equation has a speed parameter "##v##" in it; why does your solution have no ##v## anywhere? Is your ##c## perhaps equal to the ##v## in the question?
 
Sorry yes my c=v my appolgise. I have also just had a through could I use the indenties for cos(a+b) and cos(a-b) to solve this problem
 
Last edited:
Taylor_1989 said:
I am not going to put full working, I am having trouble with one particular part the intial condtions for my Fourier series.

Homework Equations


$$U_t(x,0)=\sum_{n=1}^\infty \left(-\frac{n\pi c}{L}\right)B_n sin(\frac{n\pi}{L}x)$$ [1]

I agree up to here except I don't have a minus sign. But that shouldn't affect the final answer.

$$\left(-\frac{n\pi c}{L}\right)B_n=\frac{2}{l}\int _0^l v_0 \sin\left(\frac{n\pi }{L}x\right)dx$$
That isn't quite right. Apparently the ##l## should be ##L##, but the function isn't ##v_0## on that interval. So it is better written$$
\left(-\frac{n\pi c}{L}\right)B_n=\frac{2}{L}\int _0^L u_t(x,0) \sin\left(\frac{n\pi }{L}x\right)dx$$ $$
\left(-\frac{n\pi c}{L}\right)B_n=\frac{2}{L}\int _{\frac L 2 - \frac a 2}
^{\frac L 2 + \frac a 2 }v_0 \sin\left(\frac{n\pi }{L}x\right)dx$$

$$B_n=-\frac{2v_0}{-n\pi c}\int _{\left(\frac{L}{2}-\frac{a}{2}\right)}^{\frac{L}{2}+\frac{a}{2}}sin\left(\frac{n\pi }{L}x\right)dx\:$$ [3]

The Attempt at a Solution



[3] soultuion
$$B_n=\frac{2Lv_0}{n^2\pi ^2c}\left(cos\left(\frac{n\pi }{2}\left(\frac{L+a}{L}\right)-cos\left(\frac{n\pi }{2}\left(\frac{L-a}{L}\right)\right)\right)\right)$$

I believe I have gone wrong with the limits and my problem lies in how the size of the hammer is effecting the wave in this case, could someone please advise, thanks in advace

I didn't check your final answer but I don't see any obvious major errors.