Wave Speed Question Homework: Length, Speed & Mass

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SUMMARY

The discussion centers on calculating the properties of a rope oscillating in a second-harmonic standing wave pattern under a tension of 200 N. The displacement of the rope is described by the equation y = (0.10m)(sin(πx/2)sin(12πt). The length of the rope is determined to be 1 meter. The wave speed can be calculated using the relationship between frequency and wavelength, and the mass of the rope can be derived once the wave speed is known. Additionally, the period of oscillation for a third-harmonic standing wave pattern is to be determined.

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Homework Statement



A rope, under a tension of 200 N and fixed at both ends, oscillates in a second-harmonic standing wave pattern. The displacement of the rope is given by

y = (0.10m)(sinPIx/2)sin12PIt

where x = 0 at one end of the rope, x is in meters, and t is in seconds. What are (a) the length of the rope, (b) the speed of the waves on the rope, and (c) the mass of the rope? (d) If the rope oscillates in a third-harmonic standing wave pattern, what will be the period of oscillation?


Homework Equations



I'm not sure...I know how to solve for the length of the rope, but I don't know which formula to use to solve for the wave speed. Although once i find this, I know how to find the mass of the rope and the period in part (d).

The Attempt at a Solution



I know you can find the length of the rope by setting

0.10 = 0.10sin(PIx/2)

because the 0.10 m in the original equation will be the amplitude of the wave, and at it's maximum, sin(12PIt) = 1. this gives you x = 1 meter.

But i don't know where to go from here, to get the velocity.

i know f = v/lambda = (nv)/(2L) and that lambda = 2L/n, but you can't use these equations to solve for velocity, because the v cancels out.
 
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There is a problem with (a). The answer does not depend on the amplitude.

Have you drawn a picture of the rope for the second-harmonic pattern? Do that, and think about how wavelength and rope length are related.
 

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