- #1

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I am doing

**m= ukmg*L\v*squared**but it is not working, am I suppose to find a new velocity or something. Any help appreciated.

- Thread starter macgirl06
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- #1

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I am doing

- #2

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Why do you say it is not working? Where did you get that equation and what do the variables mean?

- #3

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- #4

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uk= 0.2000

m= 53.6 kg

g= 9.8

v= 1.14

L=4.60

It seems like a very easy question but I don't know where I am messing up.

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- #6

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its mass...

- #7

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M=uk*m*g*L\v^2

so I'm stuck also. You'll have to hope someone else does since you haven't explained it.

- #8

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- #9

Doc Al

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There's nothing wrong with that equation, which is derived from the formula for the speed of a wave (or pulse) on a stretched rope:I am doingm= ukmg*L\v*squaredbut it is not working, am I suppose to find a new velocity or something.

[tex]v^2 = \frac{T}{\rho}[/tex]

Where T is tension in the rope (which equals the friction force [itex]\mu m_{person} g[/itex]) and [itex]\rho = m_{rope}/L[/itex].

I'll rewrite that equation like this:

[tex]m_{rope} = \frac{\mu m_{person} g L}{v^2}[/tex]

v should be the speed

uk= 0.2000

m= 53.6 kg

g= 9.8

v= 1.14

L=4.60

It seems like a very easy question but I don't know where I am messing up.

- #10

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- #11

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- #12

Doc Al

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To find the speed of the pulse just use the distance it travels (the length of the rope) and the time it takes (which is given).

Yes.

- #13

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k got it, just a calculational error on my part. Thanks again for the clarification...:)

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