Wavelength of em radiation of H - atom

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SUMMARY

The discussion centers on calculating the wavelength of electromagnetic radiation emitted by a hydrogen atom during a transition from a higher energy level to a lower one. The energy difference calculated is 10.2 eV, which corresponds to a wavelength of 1.22 x 10-5 cm using the formula λ = hc/E. The conclusion confirms that the calculated wavelength aligns with option (a) provided in the homework question.

PREREQUISITES
  • Understanding of the Bohr model of the hydrogen atom
  • Familiarity with the energy levels of hydrogen
  • Knowledge of the relationship between energy, wavelength, and frequency (E = hc/λ)
  • Basic proficiency in converting energy units from eV to wavelength
NEXT STEPS
  • Study the Bohr model of the hydrogen atom in detail
  • Learn about the calculation of wavelengths for transitions in hydrogen using the Rydberg formula
  • Explore the concept of energy level diagrams for hydrogen and other elements
  • Investigate the implications of electromagnetic radiation in quantum mechanics
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in quantum mechanics and atomic structure, particularly those studying the properties of hydrogen and electromagnetic radiation.

Pushoam
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Homework Statement


upload_2017-12-12_14-28-46.png

Homework Equations

The Attempt at a Solution


E = (13.6 – 3.4 = 10.2)eV = ## \frac {hc } { \lambda } ##

=1.22 * 10^{-5} cm

So, the correct option is (a).
Is this correct?
 

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