Wavelength of Light: 0.544µm in Air & Water

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Homework Help Overview

The discussion centers around the wavelength of light as it transitions from air to water, specifically for light with an initial wavelength of 0.544 µm in air. The problem involves understanding how the speed of light changes in different media and its relationship to wavelength and frequency.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply formulas related to mechanical waves to the problem of light waves, leading to confusion about the correct equations to use. Some participants question the appropriateness of the equations being used and suggest a need for a deeper understanding of the underlying concepts.

Discussion Status

Participants are actively engaging in clarifying the concepts related to the speed of light and its relationship with wavelength and frequency. Some hints have been provided to guide the original poster towards a more suitable approach, but there is no explicit consensus on a solution yet.

Contextual Notes

There is a noted misunderstanding regarding the speed of light in air, as well as the application of formulas that are not relevant to light waves. The original poster's attempts suggest a need for further exploration of the topic.

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Homework Statement


Light of wavelength 0.544 µm (in air) enters the water in a swimming pool. The speed of light in water is 0.700 times the speed in air. What is the wavelength of the light in water?


Homework Equations


mu = m / L

v = sqrt (F/mu)

speed of air 386 m/s

The Attempt at a Solution


0.700 x 386 = 270.2

270.2 = sqrt (F / 0.544) = 39716.40

F = 39716.40

idk what to do now
 
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The equations you are using do not apply to light waves. Your formula for a velocity is for a mechanical wave on a string, not a light wave. 386m/s is NOT the speed of light in air, not even close.

Forgive me if I'm wrong, but it seems you are trying to plug and chug equations to get an answer for this problem without even considering what the equations mean. You have to go and seriously read the chapter on this topic in your book if you haven't done so. Trying to mindlessly plug an chug equations is a recipe for disaster in a physics course.

I will give you a few hints to get you on the right path:

The speed of light is related to the light's wavelength and frequency by:

[tex]\lambda f=v[/tex]

The speed of the light depends on the medium and is given by:

[tex]v=c/n[/tex], where n is the index of refraction of the medium.

c is the speed of light in a vacuum:

[tex]c=\lambda_{vac}f=3*10^8 m/s[/tex]

The frequency of the light will remain the same in all media.

Using this information, can you solve the problem?
 
thanks for help
 
how do i do this problem?
 
As GO1 said, use the relation between wavelength, frequency, and speed:

f = v/λ

And this:

G01 said:
The frequency of the light will remain the same in all media.

Using the fact that f is the same for the light in air or water, work with the above equation.
 

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