Waves, Bungee Jumping, Linear Density Definition

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SUMMARY

The discussion centers on the calculation of linear density (μ) in the context of wave mechanics related to bungee jumping. A participant asserts that the correct linear density should be 89.9 N/m, derived from the formula μ = mass/length, specifically μ = 75 x 10-3 kg / 1.8 m. This correction addresses an error in the book's calculations, emphasizing the importance of accurate measurements in physics problems.

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  • Ability to perform calculations involving mass and length
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alingy1
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Please look a picture.
I think the book made a mistake.
The answer should be 89.9N/m.
Why? Because they calculated the linear density μ wrongly. They should have done $$\frac{75*10^{-3}kg}{1.8m}$$
 

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alingy1 said:
Please look a picture.
I think the book made a mistake.
The answer should be 89.9N/m.
Why? Because they calculated the linear density μ wrongly. They should have done $$\frac{75*10^{-3}kg}{1.8m}$$
I'm pretty sure that you are correct !
 

Thread 'Magnitude of buoyant force in fluids of different densities'

The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?
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