First off, this is my first post, so hi everybody, this looks like a good place I can get some real help possibly. I am taking a Physics I with Calc course at my college and I am having to use an internet based homework service that comes with our textbook called WebAssign. This seems to be hindering me at my work a little so be gentle if the solution is blindingly obvious. Thank you.(adsbygoogle = window.adsbygoogle || []).push({});

1. The problem statement, all variables and given/known data

Every morning at seven o'clock

There's twenty terriers drilling on the rock.

The boss comes around and he says, "Keep still

And bear down heavy on the cast-iron drill

And drill, ye terriers, drill." And drill, ye terriers, drill.

It's work all day for sugar in your tea

Down beyond the railway. And drill, ye terriers, drill.

The foreman's name was John McAnn.

By God, he was a blamed mean man.

One day a premature blast went off

And a mile in the air went big Jim Goff. And drill...

Then when next payday came around

Jim Goff a dollar short was found.

When he asked what for, came this reply:

"You were docked for time you were up in the sky."

And drill...

-- American folksong If Goff actually went 1.00 mile in the air and was docked exactly $0.95, what was Goff's hourly wage?

2. Relevant equations

We are given several kinematic equations to work with in this chapter. I am assuming this falls under free falling motion with constant acceleration due to gravity.

I was using this equation: x_{f}= x_{i}+ v_{xi}t + (1/2)a_{x}t^{2}

3. The attempt at a solution

I am not sure that I signed up for poetic interpretation with my physics course, but apparently they expect me to be creative aswell. The only way I can interpret this problem is saying that he was shot up (apparently almost instantly) 1 mile into the air. At this point when he obtains his maximum height his velocity should be 0. From this point on he falls due to the constant acceleration of gravity which in this case would be -9.80.

In order to obtain the time that it took for him to reach the ground we need to substitute the known information into the equation (I convert 1 mile into 1609 meters using SI units) and solve for t. Doing this I get:

x_{f}= x_{i}+ v_{xi}t + (1/2)a_{x}t^{2}

0 = 1609 + 0t + (1/2)(-9.80)t^{2}

Solving for t I obtain:

t = 18.1209 seconds.

From this information. It would lead me to believe that Goff was docked $0.95 for being in the air for 18.1209 seconds. This would lead to a huge hourly wage.

So he was docked $0.95 for .005 hours. This would lead to a huge hourly wage and I know i am doing something wrong. I just do not understand. I do not see how any other equations will work with this problem and the given information. If anyone can help it would be much appreciated.

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# WebAssign Homework - Basic Acceleration Problem

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