Webpage title: Understanding the Direction of Electron Flow in Circuits

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SUMMARY

This discussion clarifies the distinction between electron flow and conventional current flow in electrical circuits. It emphasizes that electron flow, characterized by the number-density current of electrons, moves in the opposite direction to the electric current-density vector due to the negative charge of electrons. The conversation references Benjamin Franklin's historical misinterpretation of current flow and highlights the Hall effect as a method to determine the charge carriers in materials, noting that metals typically have negatively charged electrons while p-doped semiconductors contain positively charged holes.

PREREQUISITES
  • Understanding of basic circuit theory
  • Familiarity with the concepts of current density and electron density
  • Knowledge of the Hall effect and its applications
  • Basic principles of semiconductor physics
NEXT STEPS
  • Research the Hall effect and its significance in determining charge carriers
  • Study the differences between electron flow and conventional current flow
  • Explore the historical context of Benjamin Franklin's contributions to electrical theory
  • Investigate the properties of p-doped and n-doped semiconductors
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Electrical engineers, physics students, educators in electronics, and anyone interested in the fundamentals of circuit theory and electron behavior in materials.

Miike012
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In the paint document you will see on the LHS a picture of a circuit diagram then on the RHS you will see a pictorial representation of an electron in the circuit located at an arbitrary point

My question (which is in the paint document): I want to know why the electrons flow in the direction that they do.
 

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Do not confuse current flow with electron flow. You may want to investigate Benjamin Franklin and his incorrect assumption about current.

I hope this helps!
 
There is a lot of confusion, because many people do not tell which flow they talk about. A flow is characterized by a current-density vector, and here there are involved at least two different vectors in this question.

The first is the number-density current of electrons in a wire. If the number density of electrons is [itex]n(t,\vec{x})[/itex] and [itex]\vec{v}(t,\vec{x})[/itex] the velocity field of the electrons, then the number-density current is [itex]\vec{J}_n(t,\vec{x})=n(t,\vec{x}) \vec{v}(t,\vec{x})[/itex]. Obviously [itex]n(t,\vec{x})>0[/itex] (giving the number of electrons per unit volume). The number-current density gives the number of electrons per unit time running through a surface element with surface-area vector [itex]\mathrm{d} \vec{F}[/itex] as
[tex]\mathrm{d}N=\mathrm{d} \vec{F} \cdot \vec{J}_n.[/tex]

The electric current-density vector [itex]\vec{j}_{\text{el}}[/itex], however, gives the charge per unit time running through the surface element. Obviously we have [itex]\vec{j}_{\text{el}}=-e \vec{J}_n[/itex], where [itex]-e<0[/itex] is the charge of one electron. This shows that the electric current-density vector points always in the opposite direction of the number-density current of electrons, simply because (by convention!) electrons are negatively charged.

You can indeed find out, whether the charge carriers of a current are positively or negatively charged by using the Hall effect:

http://en.wikipedia.org/wiki/Hall_effect

It turned out that in metals the charge carriers carry negative charge, while in some semiconductors the charge carriers are negatively charged. In the case of metals the charge carriers are (medium modified) electrons and in the case of p-doted semiconductors positively charged quasiparticles, i.e., electron holes in the Fermi sea.
 

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