Weighing an Object in Water: Does the Bouyant Force Matter?

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SUMMARY

The discussion centers on the effects of buoyant force on an object placed on a weighing machine at the bottom of a swimming pool. It is established that an object with a density greater than water will weigh less when submerged due to the buoyant force acting on it. The buoyant force affects the entire object, not just the lower surface, and for accurate weight measurement, the bottom of the object must be sealed to the scale to eliminate buoyancy effects. The conversation also highlights a simple experiment demonstrating similar principles using air pressure.

PREREQUISITES
  • Understanding of buoyancy and Archimedes' principle
  • Basic knowledge of pressure dynamics in fluids
  • Familiarity with weight measurement techniques
  • Concept of sealed systems in physics experiments
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  • Research Archimedes' principle and its applications in fluid mechanics
  • Explore experiments demonstrating buoyancy with various materials
  • Learn about pressure measurement techniques in fluids
  • Investigate the effects of sealing systems on buoyant forces
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Students of physics, educators teaching fluid dynamics, and anyone interested in understanding the principles of buoyancy and weight measurement in fluids.

phymatter
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if i place a weighing machine at the bottom of the swimming pool and then put a box on it whose density is greater than the iquid , then will it weigh more or less , as compared to on the land ?
i think that it will weigh less , but if its lower surface is in contact with the surface of the swimming pool then how can it experience the buoyant force??
this is troubling me , please help! :confused:
 
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Are you suggesting that if you placed a very light, say rubber, cube on the bottom of the swimming pool it would not float? Bouyancy affects the entire object, not just its lower side.
 
HallsofIvy said:
Are you suggesting that if you placed a very light, say rubber, cube on the bottom of the swimming pool it would not float? Bouyancy affects the entire object, not just its lower side.

no , i mean that if we put a very heavy box which rests compleatly on the weighing machine so that there is no exposed area at the bottomof the box where the force due to upward pressure could be exerted , sure the pressure will be exerted from the top , which will cause the weight to increase , the side forces will cancel , but there will be no way for upword buoyant force to act !
 
You would need to actually seal the bottom surface to the scale (and the scale would need to be sealed) to eliminate the buoyant force.
 
If the object had a perfectly flat bottom, with perfect contact with the floor of the tank and vertical sides then there would be no upward vertical forces on it. The weight would measure as the object's weight plus the weight of water on top.

There is a simple experiment to show the same effect, this time with air. Lay a newspaper, spread out, on a table with a ruler half under the paper. Then try to lift the ruler quickly. The excess pressure above will temporarily resist you forcibly - until some air leaks in underneath the paper.
 
thank you everyone ! this forum rocks! :)
 
Yes it certainly does and, d'you know another great thing about it? Hardly anybody ever whinges or gets too upset. I've followed some forums which are full of fanciful weeds who don't want to know about real Science at all but they sob sob when that's pointed out.
We're well mature innit.
 

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