Weight on an Incline: Understanding Angles

1 reply · 3K views · last reply
pooface
Messages
207
Reaction score
0
There is not really a homework problem. I just want to understand the concept here.

See the image attached. How is it that in the free body diagram of the image shown the angle theta is from FN to the perpendicular Force applied by box to the horizontal? It is hard to describe in words. I just want to know how am I placing my angles and X,Y in a free body diagram of this setup.

I always thought the X axis was Cos and Y was Sin but when my professor solved the problem, FN, which is vertical, was determined by FN cos(theta)

I don't understand.
 
Attachments
  • Free-body diagram of a box on a tilted incline at angle theta, with applied force Fa up the slope, weight FW = 200 N straight down, normal force FN perpendicular to the surface, and theta marked between the vertical and the normal force.
    elevation FN.JPG
    5.2 KB · Views: 508
The two thetas are equal from similair triangles.
Rather than trying to remmber which is cos and sin think what happens as the angle gets small, which force goes to zero ,that equals sin which goes to zero as theta is small,and which gets larger, that is cos goes to one as theta gets small.