Ferris Wheel Physics: Solving for Weightlessness Velocity

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SUMMARY

To achieve weightlessness at the top of a 15-meter diameter ferris wheel, the centripetal acceleration must equal the acceleration due to gravity (g). This occurs when the only force acting on the person is gravity, resulting in a state of freefall. The required velocity can be calculated using the formula for centripetal acceleration, where the centripetal acceleration (a_c) equals g (approximately 9.81 m/s²). Therefore, the velocity must be determined such that a_c = v²/r, where r is the radius of the ferris wheel.

PREREQUISITES
  • Understanding of centripetal acceleration
  • Basic knowledge of gravitational force
  • Familiarity with circular motion equations
  • Ability to manipulate algebraic equations
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  • Calculate centripetal acceleration using the formula a_c = v²/r
  • Explore the relationship between velocity and radius in circular motion
  • Learn about freefall conditions in physics
  • Investigate real-world applications of weightlessness in amusement park rides
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Physics students, educators, and anyone interested in the principles of motion and forces in circular dynamics.

brendan3eb
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I have a problem asking me what velocity must be achieved so that a person on at the top of a ferris wheel with a 15-m diameter can feel weightless. I am wondering how you define weightless. At first I tried setting mg=0, but I couldn't get anywhere that way.
 
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At the top of the ferris wheel, a person is weightless when the only source of centripetal force (the inwards force) is gravity. For that brief moment, the person is in freefall.
 
Weightlessness is simply where your acceleration exactly matches the local acceleration due to gravity.
 
Right, so putting that together, you need to calculate the speed at which the centripetal acceleration equals g.

Is this a homework problem...?
 

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