Were is the electric field zero?

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SUMMARY

The net electric field intensity at the origin due to two charges, Q1 = 2μC located at (3, 4) and Q2 = -10μC at (6, -8), is calculated to be E = 3236i - 10069j. To achieve a net electric field of zero at the origin, a third charge of magnitude 5μC must be placed along the line of the electric field vector in the opposite direction. The exact coordinates for this placement can be determined by dividing the negative of the electric field vector by the constant k associated with the charge's influence.

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blackblanx
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Homework Statement



What is the net electric field intensity at the origin due to two charges Q1= 2\muC at (x=3,y=4) and Q2 = -10\muC at (x=6,y=-8). And where should a third charge of magnitude 5 \muC be placed so the net electric field at the origin is zero?

Homework Equations


E=KQ/R^{2} \widehat{r}

The Attempt at a Solution



I have found the first part of the question to be E= 3236\widehat{i}-10069\widehat{j} but I am not sure how you would find out were to place the third charge. Please help
 
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Hi blackblanx! :smile:

(have a mu: µ :wink:)
blackblanx said:
… And where should a third charge of magnitude 5 \muC be placed so the net electric field at the origin is zero?

I have found the first part of the question to be E= 3236\widehat{i}-10069\widehat{j} but I am not sure how you would find out were to place the third charge. Please help

The third charge will have to supply a field of minus E. :wink:
 
tiny-tim said:
Hi blackblanx! :smile:

(have a mu: µ :wink:)


The third charge will have to supply a field of minus E. :wink:


but what are the coordinates of where that charge should be placed?
 
oh wait never mind i think i got it know thanks it would just be the negative of the electric field vector divided by k(5\muC)
 
Forget I realized that does not work any ideas of how to find the coordinates?
 
It'll be on the line in the direction of E, at the distance appropriate to the given strength. :smile:
 
ok thanks
 

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