Were is the electric field zero?

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Homework Help Overview

The problem involves calculating the net electric field intensity at the origin due to two charges, Q1 and Q2, and determining the position for a third charge such that the net electric field at the origin is zero.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of the electric field from the two given charges and express uncertainty about how to determine the placement of the third charge. There are attempts to clarify the relationship between the electric field and the required position of the third charge.

Discussion Status

Some participants have provided insights about the necessary conditions for the third charge to achieve a zero net electric field, while others are exploring the specific coordinates for its placement. The conversation reflects a mix of understanding and ongoing inquiry without a clear consensus on the solution.

Contextual Notes

Participants are navigating the complexities of electric field calculations and the implications of charge placement, with some expressing confusion about the methodology and assumptions involved.

blackblanx
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Homework Statement



What is the net electric field intensity at the origin due to two charges Q1= 2[tex]\mu[/tex]C at (x=3,y=4) and Q2 = -10[tex]\mu[/tex]C at (x=6,y=-8). And where should a third charge of magnitude 5 [tex]\mu[/tex]C be placed so the net electric field at the origin is zero?

Homework Equations


E=KQ/R[tex]^{2}[/tex] [tex]\widehat{r}[/tex]

The Attempt at a Solution



I have found the first part of the question to be E= 3236[tex]\widehat{i}[/tex]-10069[tex]\widehat{j}[/tex] but I am not sure how you would find out were to place the third charge. Please help
 
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Hi blackblanx! :smile:

(have a mu: µ :wink:)
blackblanx said:
… And where should a third charge of magnitude 5 [tex]\mu[/tex]C be placed so the net electric field at the origin is zero?

I have found the first part of the question to be E= 3236[tex]\widehat{i}[/tex]-10069[tex]\widehat{j}[/tex] but I am not sure how you would find out were to place the third charge. Please help

The third charge will have to supply a field of minus E. :wink:
 
tiny-tim said:
Hi blackblanx! :smile:

(have a mu: µ :wink:)


The third charge will have to supply a field of minus E. :wink:


but what are the coordinates of where that charge should be placed?
 
oh wait never mind i think i got it know thanks it would just be the negative of the electric field vector divided by k(5[tex]\mu[/tex]C)
 
Forget I realized that does not work any ideas of how to find the coordinates?
 
It'll be on the line in the direction of E, at the distance appropriate to the given strength. :smile:
 
ok thanks
 

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