oblong-pea said:
TL;DR Summary: I know U-235 is the fissile part, but what happens to the U-238 parts during reaction and after?
So I'm aware that uranium 235 is the fissile isotope which is used in fuel for most reactors (about 3% of all uranium fuel for example), but what actually happens to the other 97% of the U-238 if it doesn't undergo fission?
I get some of it absorbs neutrons making it U-239? But I've also seen it can become Plutonium-239? But what actually happens to the rest, does it lay dormant and non-fissile? And how do they know when the fuel is depleted?
Some
238U fissions from fast neutrons, which provide about 7-8% of all fissions, and some of
238U aborbs a neutron and become
239U, which undergoes successive beta decay to
239Np to
239Pu, and
239Pu is quite fissile, and provides a considerable fraction of fissions as
235U depletes. Modern power reactors use enrichments up 4.95% (less than 5% - some uncertainty). Typical burnups are up to 50 to 60 GWd/tU, or about 5 to 6% of initial metal atoms (consumed). At those burnups, most of the fission is coming from Pu.
What isn't fissioned or transmuted remains as is -
238U - which could be recycled, but the recycle U often contains
236U (converted from
235U), which is disadvantageous.
As V50 indicated, the spent fuel, which includes unused U, various transmuted products (transuranics), and the fission products, sits in spent fuel pools at the reactor site, where it cools. At some point, the older/aged spent fuel is transferred to dry (inert He) filled storage containers, which are stored at the reactor site. The US does not reprocess fuel, while some European and Asian nations do reprocess spent fuel and recycle the U and Pu, and perhaps some transuranics.