What are common issues when using 2N2222 in a BJT NPN amplifier?

  • Thread starter Thread starter Ivan Antunovic
  • Start date Start date
  • Tags Tags
    Bjt Npn Transistor
Click For Summary
SUMMARY

The forum discussion centers on troubleshooting issues with a BJT NPN amplifier using the 2N2222 transistor. Key problems identified include the absence of AC voltage at the output due to potentially incorrect operating points, the negligible hybrid output resistance (hoe), and uncertainties regarding the small signal analysis schematic. Participants emphasize the importance of coupling capacitor values and suggest that the design may be flawed, particularly with low resistance values affecting performance.

PREREQUISITES
  • Understanding of BJT amplifier configurations, specifically common emitter amplifiers.
  • Familiarity with transistor parameters such as Vce, Ic, and Vbe.
  • Knowledge of signal analysis techniques, including small signal models.
  • Basic circuit analysis skills, including the use of load lines and voltage dividers.
NEXT STEPS
  • Research the impact of coupling capacitor values on amplifier performance, particularly at low frequencies.
  • Learn how to calculate the hybrid output resistance (hoe) and its relevance in amplifier design.
  • Investigate the design principles for common emitter amplifiers, focusing on biasing techniques and resistor selection.
  • Explore simulation tools for circuit analysis to validate amplifier designs and troubleshoot issues effectively.
USEFUL FOR

Electronics students, hobbyists designing audio amplifiers, and engineers working with BJT transistor circuits will benefit from this discussion.

Ivan Antunovic
Messages
109
Reaction score
4
Hello people,

I am working on a BJT NPN amplifier the model that I've choosen is 2N2222 : http://www.e-voron.dp.ua/files/pdf/tranzistor/2N2222.pdf

I am having 3 problems here:

1) am not having any AC voltage at output Vce seems like I have set wrong operating point?

2) I am trying to figure out how to determine hoe resistance of this transistor from the graph hybrid output resistance hoe=dIc/dUce at operating point Q

3)Is my schematics for the small signal analysis wrong?

I hope pictures are not blur.
 

Attachments

  • BJT NPN Shema.jpg
    BJT NPN Shema.jpg
    79.9 KB · Views: 562
  • DSC_0789 (1).JPG
    DSC_0789 (1).JPG
    17.4 KB · Views: 483
  • DSC_0790 (1).JPG
    DSC_0790 (1).JPG
    25.6 KB · Views: 470
Physics news on Phys.org
Okay they are blur
BJT_NPN_Shema.jpg

DSC_0792.jpg

http://postimage.org/
 
Last edited by a moderator:
Ivan Antunovic said:
Okay they are blur
BJT_NPN_Shema.jpg
and Xce should be in parallel with Re my bad
DSC_0792.jpg

http://postimage.org/
 
Last edited by a moderator:
Ivan Antunovic said:
Hello people,

I am working on a BJT NPN amplifier the model that I've choosen is 2N2222 : http://www.e-voron.dp.ua/files/pdf/tranzistor/2N2222.pdf

I am having 3 problems here:

1) am not having any AC voltage at output Vce seems like I have set wrong operating point?

What's your frequency and amplitude? Your RC and RT are both very low.
2) I am trying to figure out how to determine hoe resistance of this transistor from the graph hybrid output resistance hoe=dIc/dUce at operating point Q
forget about hoe. It's negligible.
3)Is my schematics for the small signal analysis wrong?
No idea. Depends on your software. Your schematic in post 2 does not show a signal source ...
 
rude man said:
What's your frequency and amplitude? Your RC and RT are both very low. forget about hoe. It's negligible.
No idea. Depends on your software. Your schematic in post 2 does not show a signal source ...

Okay forgotten to say about voltage source it's sinus with amplitude 100 mV and frequency 50Hz
 
Ivan Antunovic said:
Okay forgotten to say about voltage source it's sinus with amplitude 100 mV and frequency 50Hz

I know that hoe is so small but I am trying to do things atleast as correct as I can I do this for my soul.There is Ic-Uce curve in the link that I've given but it's in logaritmic paper how to I convert it from dB to Ampers and Volts?
 
Due to C1 being so large you should be seeing a horribly distorted sine wave at the collector of about 200 mV.
At the output there is very little ac since the time constant formed by RC, RT and CV2 is very low (cutoff freq. about 2 KHz).

This is a really bad design so worrying about hoe is a total waste of time.
What does your simulator say?

.
 
rude man said:
Due to C1 being so large you should be seeing a horribly distorted sine wave at the collector of about 200 mV.
At the output there is very little ac since the time constant formed by RC, RT and CV2 is very low (cutoff freq. about 2 KHz).

This is a really bad design so worrying about hoe is a total waste of time.
What does your simulator say?

.
I have taken schematics from the internet,voltmeter shows no voltage at output and oscilloscope shows no signal at output
 
Ivan Antunovic said:
Okay forgotten to say about voltage source it's sinus with amplitude 100 mV and frequency 50Hz

For a signal frequency of 50Hz your coupling capacitors are way too small; they are attenuating the signal more than the 2222 is amplifying it. What is the reactance of a 1uF capacitor at 50Hz?
 
  • #10
NascentOxygen said:
For a signal frequency of 50Hz your coupling capacitors are way too small; they are attenuating the signal more than the 2222 is amplifying it. What is the reactance of a 1uF capacitor at 50Hz?
it's 3813 ohms.Okay then make it 10kHz so the reactance goes down by 200
 
  • #11
Forget about this task it has very bad resistances.

I got a new task from my professor:

Compile common emmiter amplifier(NPN) with the following default parameters:

VCC = 12V, power transistor 50 mW max. output signal between 3-5V, VRE = 1V.

Determine Computing and measuring AV, AI, Rin, Rout, the upper and lower limit frequency, THD.

Then, instead of RL connect the speaker and try something heard on the speaker.

I have choosen transistor BC547.

I assumed that the voltage at RL is 5V and from PRL=VRL^2 / RT I get that RL=250 ohms.I measured that Vbe=0.68V.

I am trying to figure out what should be resitances R1 and R2
transistor.jpg
image upload no limit
 
  • #12
Ivan Antunovic said:
Forget about this task it has very bad resistances.

I got a new task from my professor:
Compile common emitter amplifier(NPN) with the following default parameters:
VCC = 12V, power transistor 50 mW max. output signal between 3-5V, VRE = 1V.
Determine Computing and measuring AV, AI, Rin, Rout, the upper and lower limit frequency, THD.
Then, instead of RL connect the speaker and try something heard on the speaker.
I have choosen transistor BC547.
I assumed that the voltage at RL is 5V and from PRL=VRL^2 / RT I get that RL=250 ohms.I measured that Vbe=0.68V.
I am trying to figure out what should be resitances R1 and R2
R1 and R2 are chosen to give you the required 1V at the emitter. Consider the base dc current also.
The professor meant to limit your dissipation to 50 mW, not that the transistor cannot sustain more than 50 mW, probably.
EDIT:
I didn't see the 1V VRE requirement. So this will not be a real common-emitter circuit.
What are your upper and lower frequencis?
You can probably connect the speaker in series with the collector resistor.
 
Last edited:
  • Like
Likes   Reactions: Ivan Antunovic
  • #13
Ivan Antunovic said:

I got a new task from my professor:

Compile common emmiter amplifier(NPN) with the following default parameters:

VCC = 12V, power transistor 50 mW max. output signal between 3-5V, VRE = 1V.
The specs say Vcc = 12V, yet your calculations use Vcc of 15V. Why? :oldconfused:
 
  • #14
NascentOxygen said:
The specs say Vcc = 12V, yet your calculations use Vcc of 15V. Why? :oldconfused:
My bad I was really tired at evening when doing this that I didn't even notice it was 15 V.
 
  • #15
How do you mean it won't be real common emitter circuit when it has a resistor RC connected directly to the collector electrode?R1 and R2 are voltage dividers I know that they are used to set Quiescent Point.If R1 and R2 are voltage dividers of Vcc and if I want 13.35 V at R1 and 1.65 V at R2,R1 should be 8.09 times larger than R2.

Edit(after drinking a coffee :D):
Btw I am using BC547 for this circuit https://www.fairchildsemi.com/datasheets/BC/BC547.pdf maybe I should take some data from the datasheet and try calculating resistances.For example there is a Ic-Vce curve and I tried to make load line and then it's a piece of cake for finding the resistances.

Load line equation is:
Ic=-Uce/Rc+Re + Ucc/Rc+Re (Asumming that Ic=Ie)the maximum Vce voltage is Vcc which is 12 volts ,maximum current Ic will flow when Ucc/Rc+Re and therefore it's y-intercept of the curve.But still I don't know Rc and Re so therefore I can't find y-intercept...maybe I should consider a worst case scenario and take values for Vce ,Ic and Ib from the datasheet?
 
Last edited:
  • #16
If you're aiming for 50mW dissipation, and you bias for VCE of around 6-7V, then what will be the DC value of IC?
 
  • #17
NascentOxygen said:
If you're aiming for 50mW dissipation, and you bias for VCE of around 6-7V, then what will be the DC value of IC?

Well I don't know since I am trying to figure out how to find R1 and R2 since they determine the bias IB and then IC.If I assume that Vce is around 6 V then VRC=VCC-VCE-VRE=12-1-6= 5 V but still I don't know the value of the resistance RC?
 
  • #18
power dissipation = voltage x current

- which voltage?
- which current?

Remember that power into the base is a negligible fraction of total power, for these small signal amplifiers.
 
  • #19
NascentOxygen said:
power dissipation = voltage x current

- which voltage?
- which current?

Remember that power into the base is a negligible fraction of total power, for these small signal amplifiers.
I think he meant power dissipated at the output load resistance
 
  • #20
Yes power into the base is negligible but I didnt understand first part of your post?
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
3K
Replies
4
Views
20K
Replies
16
Views
10K
Replies
11
Views
3K
  • · Replies 25 ·
Replies
25
Views
9K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K