What Are Complex Numbers and How Can Beginners Start Learning About Them?

[lurflurf]

Since the instruction says to find all solutions, doesn't that mean ln have to be multivalued? Multivalued means k>0, right? k=0 would be the principle value, which is single valued, isn't it?
Can you check the attachment?

That attachment is fine.
It is a minor technicality. To find all solutions we can use a multivalued inverse, or we can use a single value inverse to generate all solutions. k=0 can be the principal value if it is set up that way

your last post is confusing
where did i^0 come from?
third line from the bottom should have 2k pi i
then it should in the next line become 2k pi when you multiply both sides by -i

 

[MissP.25_5]

That attachment is fine.
It is a minor technicality. To find all solutions we can use a multivalued inverse, or we can use a single value inverse to generate all solutions. k=0 can be the principal value if it is set up that way

your last post is confusing
where did i^0 come from?
third line from the bottom should have 2k pi i
then it should in the next line become 2k pi when you multiply both sides by -i

Sorry, it should be i*0, this is due to iargZ. And argZ here is 0.

 

[MissP.25_5]

That attachment is fine.
It is a minor technicality. To find all solutions we can use a multivalued inverse, or we can use a single value inverse to generate all solutions. k=0 can be the principal value if it is set up that way

your last post is confusing
where did i^0 come from?
third line from the bottom should have 2k pi i
then it should in the next line become 2k pi when you multiply both sides by -i

So, is this okay now?

 

[lurflurf]

^Yes that looks good.

 

[MissP.25_5]

^Yes that looks good.

Between the 2 terms, (regarding the final answer) the symbol is just + or is it +/- ? I mean, how to simplify it?

 

[lurflurf]

^Which 2? We need +/- either in front of log or between 2 and √3. We do not need it with 2k π unless we require k to not be negative.

 

[MissP.25_5]

^Which 2? We need +/- either in front of log or between 2 and √3. We do not need it with 2k π unless we require k to not be negative.

Okay, I got it now! Thank you so much for being patient with me.