What are the eigenvalues and eigenfunctions for T(f(x)) = 5f(x) on C for V:R->R?

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Homework Help Overview

The discussion revolves around the linear transformation T defined on the space of continuous functions C, specifically the equation T(f(x)) = 5f(x). Participants are tasked with identifying the eigenvalues and eigenfunctions associated with this transformation.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Some participants question the nature of eigenvalues and eigenfunctions in the context of function transformations, expressing uncertainty about how to approach the problem. Others suggest that since T multiplies functions by 5, this implies that 5 is the eigenvalue and any function could be an eigenfunction.

Discussion Status

The conversation is ongoing, with participants exploring the implications of the transformation T. Some have provided insights into the definition of eigenvalues and eigenfunctions, while others are seeking more complex examples to deepen their understanding.

Contextual Notes

Participants express confusion regarding the application of eigenvalue concepts to function transformations as opposed to matrix operations. There is also mention of differential equations as a related topic for more complex problems.

glueball8
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Homework Statement


T(f(x)) = 5 f(x)
T is defined on C. Find all real eigenvalues and real eigenfunction. V:R -> R

Homework Equations


Not sure.


The Attempt at a Solution


No, clue. I can find eigenvalues for matrices, that's not a problem. I'm having problem that its a T(function) = something function, how do I solve a problem like this in general?

Any hints?

Thanks
 
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Mark44 said:
Isn't 5 the eigenvalue?

:redface: Bad example. So the eigenfunction is any function?

Uh how to do theses in general? Can you make up something more complicated and explain how to do it?

Or a link?
 
How about using the definition of "eigenvalue": If T is a linear transformation that maps functions into functions, then [itex]\alpha[/itex] is an "eigenvalue" and a non-zero function, f(x), is an eigenvector if and only if [itex]Tf(x)= \alpha f(x)[/itex]. If you are told that Tf(x)= 5f(x) for all f, then, yes, 5 is the only eigenvalue and every function in the space is an eigenvector. T just "multiplies by 5" and is exactly the same as a diagonal matrix having all "5" on its diagonal.
 
glueball8 said:
:redface: Bad example. So the eigenfunction is any function?
If all T does is multiply a function by 5, then yes.

Uh how to do these in general? Can you make up something more complicated and explain how to do it?
Usually, you solve a differential equation. Equations like the Legendre's differential equation, the Bessel's differential equation, and the Schrödinger equation are all of this form.

The differential equation [itex]y'-\lambda y=0[/itex] is a simple example. You could write it as

[tex]D(y) = \lambda y[/tex]

where D is the derivative operator. The solution to this equation [itex]y=e^{\lambda x}[/itex] is an eigenfunction of D.

Did you have a specific type of problem in mind?
 
Ok cool. :)

How about T(f(x)) = 4f(-x) + f'(x) + 6f(6)? (Might not be do able) Or something like that?

Thanks
 
Give us an actual problem, not something you just made up.
 

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