What are the factors to consider when calculating heat change in a wire loop?

  • Context: Undergrad 
  • Thread starter Thread starter TheWire247
  • Start date Start date
  • Tags Tags
    Change Heat Loop Wire
Click For Summary

Discussion Overview

The discussion revolves around calculating heat change in a wire loop, focusing on the application of Fourier's Law in this context. Participants explore the parameters involved in the calculation, including power, thermal conductivity, and geometric factors related to the wire and loop.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant proposes using the surface area of the wire, calculated as 4π²ar, for A in Fourier's Law.
  • Another participant agrees that A is the surface area of the wire and suggests that Δx is the distance between the endpoints of the wire loop.
  • There is a question about what is meant by "end points," with some participants interpreting it as the length of the wire.
  • A participant raises a concern about the clarity of the setup, noting that the term 'loop' implies there are no ends, which complicates the concept of a temperature difference necessary for heat flow.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the definition of endpoints in the context of a loop and whether a temperature difference can be established in such a configuration. The discussion remains unresolved regarding the implications of these factors on the heat change calculation.

Contextual Notes

There are limitations in the discussion regarding the assumptions about the geometry of the wire loop and the conditions necessary for heat flow, particularly the need for a temperature difference.

TheWire247
Messages
15
Reaction score
0
I am trying to calculate what the heat change from room temperature is in a wire loop is. I have the power P, the thermal conductivity K , the radius of the wire "a" and the radius of the loop "r". Using Fourier's Law:

P = -KA \frac{\Delta T}{\Delta x}

I am unsure what to use as A and \Delta x. I have the idea that A would be surface area of the wire (4 \pi^{2} a r) and \Delta x would be the just a. Is my thinking right?
 
Science news on Phys.org
A is indeed the surface of the wire. Delta(x) is the distance between the end points. With the radius of the loop you should be able to get delta(x)!
 
What do you mean by the end points. Is that the length of the wire?
 
TheWire247 said:
What do you mean by the end points. Is that the length of the wire?

Yes!
 
The set-up still isn't clear. 'Loop' implies no ends; between what points is there a temperature difference? Without a temperature difference no heat will flow.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 27 ·
Replies
27
Views
6K