What are the first partial derivatives of a definite integral function?

Click For Summary
SUMMARY

The discussion focuses on finding the first partial derivatives of the function defined by the definite integral f(x,y) = ∫(x to y) cos(t²) dt. The correct application of the Leibniz rule is confirmed, indicating that the partial derivative with respect to x is cos(x²) and the partial derivative with respect to y is -cos(y²). This demonstrates the proper handling of variable limits in definite integrals.

PREREQUISITES
  • Understanding of definite integrals and their properties
  • Familiarity with the Leibniz rule for differentiation under the integral sign
  • Basic knowledge of partial derivatives
  • Concept of variable limits in integration
NEXT STEPS
  • Study the Leibniz rule for differentiation in detail
  • Learn about the properties of definite integrals
  • Explore examples of partial derivatives in multivariable calculus
  • Investigate applications of definite integrals in physics and engineering
USEFUL FOR

Students studying calculus, particularly those focusing on multivariable functions and integration techniques, as well as educators teaching these concepts.

icosane
Messages
48
Reaction score
0

Homework Statement



Find the first partial derivatives of the function.

f(x,y) = definite integral (limits of integration x to y) cos(t^2) dt


The Attempt at a Solution



Is the partial derivative with respect to x just cos(x^2), and for y, cos(y^2) ? Or should the partial derivative with respect to y be negative?
 
Physics news on Phys.org
Sure. -cos(y)^2 for the y derivative. That's what the Leibniz rule says, right?
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
9
Views
2K
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
1K