What are the forces and angles involved in dragging a sled with ropes?

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SUMMARY

The discussion focuses on calculating the force required for two players to drag a sled with a coach at a steady speed of 1.80 m/s, overcoming a friction force of 1220 N. The angle between the two ropes is 15 degrees, which affects the effective pulling force. To determine the necessary force each player must exert, participants are advised to use trigonometric functions, specifically F*cos(15) or F*sin(15), to resolve the pulling force into components. The total pulling force must equal twice the effective force needed to counteract the friction.

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  • Understanding of basic physics concepts, particularly forces and friction.
  • Knowledge of trigonometry, specifically sine and cosine functions.
  • Familiarity with vector resolution in physics.
  • Ability to apply Newton's laws of motion in practical scenarios.
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  • Review the principles of static and kinetic friction in physics.
  • Study trigonometric functions and their applications in vector resolution.
  • Learn how to apply Newton's second law to solve force-related problems.
  • Practice similar problems involving forces at angles to strengthen problem-solving skills.
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of forces and motion, particularly in sports science or physical education contexts.

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Homework Statement



A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes. The friction force on the sled is 1220 and the angle between the two ropes is 15.0. How hard must each player pull to drag the coach at a steady 1.80 ?


Homework Equations



Not sure on what equations to use.

The Attempt at a Solution



Haven't really attempted it cause I don't know how to start it. If someone could just give me the equations to use, I think I could get it.

Thanks
 
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The pullers must match the force of friction. Their pulling force is partly wasted because they are not pulling straight ahead. You must sketch a vector at 15 degrees away from straight ahead, sketch in the rest of the right triangle of which the vector is the hypotenuse. Then use trigonometry to find the part of the F that is straight ahead. It will be F*cos(15) or F*sin(15). Finally, twice that will be equal to the friction force and you can then solve for F.
 
Please use units when posting quantities. They are meaningless without them.
 

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