What are the key differences between discrete and continuous PMFs?

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The discussion focuses on the differences between discrete and continuous probability mass functions (PMFs) using a specific PMF example. The participant calculates probabilities for three scenarios involving discrete values of X and concludes that all three parts yield the same result of 3/15. They express concern about potential trick questions regarding the continuous intervals but ultimately receive confirmation that their reasoning is correct. The conversation highlights the importance of understanding the distinction between discrete and continuous PMFs in probability theory. Overall, the thread reinforces that the problem is straightforward in the context of discrete distributions.
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Homework Statement


Let P_{x}(x) = \frac{x}{15}, x = 1,2,3,4,5 ; 0 elsewhere
be the pmf of X. Find P(X=1 or 2), P(1/2 < X < 5/2), P(1 ≤X≤2).

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The Attempt at a Solution


I believe what this problem is trying to show is the difference between discrete and continuous Pmf functions.

First, I believe the answer to ALL three parts is 3/15 as this is a discrete interval for x.
However, what is throwing me off is the continuous intervals in P(x).

Let me explain my answers:
1) If X = 1 or 2 then this is the easy solution of 1/15+2/15.
2) if we have the interval 1/2 < x < 5/2 well, the only x values that matter are still x = 1 or x = 2. Same answer.
3) Similarly, we have 1 and 2 included, so 3/15.

Am I doing anything wrong here? Is my thinking correct?

Thank you.
 
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RJLiberator said:
Is my thinking correct?
You have the correct answers. Your thinking is correct - unless you are taking a very advanced course that expects you to derive the answers using generalized definitions of integration.
 
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Perfect, thank you much for the confirmation.
I just didn't want it to end up being a trick question considering all three parts have the same answer. So the question just wanted to clarify discrete vs. continuous after all.

Cheers.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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