What are the pin reactions at A and D?

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Homework Help Overview

The problem involves determining the pin reactions at points A and D in a system subjected to couples acting at the midpoints of bars AB and BD, with the weights of the members neglected.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss breaking down the reactions into components and using free body diagrams to derive equilibrium equations. There are attempts to sum moments and forces, with some questioning the correctness of their calculations and assumptions.

Discussion Status

Participants are actively engaging with the problem, offering suggestions for drawing free body diagrams and clarifying the use of sign conventions. There is a mix of interpretations regarding the setup and calculations, with some participants expressing uncertainty about their approaches.

Contextual Notes

There is mention of neglecting the weights of the members, and participants are exploring the implications of this assumption on their calculations. Some express confusion about the relationships between the forces and moments at different points in the system.

MrMechanic
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Homework Statement


The two couples act at the midpoints of bars AB and BD. Determine the magnitudes of the pin reactions at A and D. Neglect the Weights of the members. [See Attachments for Figure]

Homework Equations


Sum Moment Along A & D = 0
Sum of Forces along X-axis
Sum forces along y-axis

The Attempt at a Solution


so i tried getting the answer at the back which is A = D = 4.22kN.
i tried moment at A
20 -20 + Rd = 0
Rd = 0?
After that i can't find a way to answer the question. Can someone guide me through it.
 

Attachments

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I would break the components of the reactions down so you have the following number of unknowns:

Rd_x and Rd_y
Ra_x and Ra_y

I would then take a free body diagram of member AB or BD to get another equation for the reactions. Then take if from there with the other equations you already listed.
 
Do you mean that I should separate each members and draw a Free-body diagram of each and do the equilibrium equations?

So i tried getting Bx and By.. by summing moments along member AB and member BD. I got Bx = 0 and By = 20/3. Can't seem to proceed from here.
 
Yes, that's what I meant.

You must have done something wrong since you should have gotten Bx = Dx and By=Dy. Summing moments for member BD then would give you one relationship between Dx and Dy.
 
I tried this one
At member AB
Sum Moment along Pin A [Clockwise Positive] = 20 - 4Bx - 3By = 0
and should i moment at Member BD?
Also, what's next at my solution. Is it correct?
 
hey Thanks i got it now. here's my solution
 

Attachments

  • 1911873_249332428583027_1258910800_n.jpg
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A couple of suggestions so that other people can understand better what you are trying to communicate:

- put a ∑ sign in front of Ma and Mb so that it is clear that you are summing up the moments about point A and B respectively; otherwise someone may be thinking you are stating the moment reactions at A and B.

- make a statement that you are explicitly looking at member BD by itself e.g. "For member BD:" or better still draw a free body diagram right at this point.

- I think your sign convention might have been mixed up but you were consistent (or just lucky) so that it still gave the right answer at the end. I would state explicitly what sign convention you are using somewhere
e.g. "[itex]\rightarrow[/itex] -ve [itex]\uparrow[/itex] +ve"
which is what I think you used in your solution.
 
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