What Are the Restricted x Values for the Integral of dx/(sqrt(d^2 + x^2))?

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The integral expression \(\int \frac{dx}{\sqrt{x^{2}+y^{2}}}\) can yield two valid results: \(\ln\left(\frac{x+\sqrt{x^{2}+y^{2}}}{d}\right)\) and \(\ln(x+\sqrt{x^{2}+y^{2}})\). The difference between these results is the constant term \(-\ln d\), where \(d\) represents a constant length related to a specific geometric context. The results are valid for all values of \(x\) and \(y\) as long as \(x^2 + y^2 \neq 0\).

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carlosbgois
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Hi there. Evaluating the expression [itex]\int\frac{dx}{\sqrt{x^{2}+y^{2}}}[/itex] I can get to the result [itex]ln(\frac{x+\sqrt{x^{2}+y^{2}}}{d})[/itex], but in my book it goes from this directly to [itex]ln (x+\sqrt{x^{2}+y^{2}})[/itex], a result wolframalpha says is valid for 'restricted [itex]x[/itex] values'. What does it mean? What are those restricted values? Why?

Many thanks.
 
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carlosbgois said:
Hi there. Evaluating the expression [itex]\int\frac{dx}{\sqrt{x^{2}+y^{2}}}[/itex] I can get to the result [itex]ln(\frac{x+\sqrt{x^{2}+y^{2}}}{d})[/itex], but in my book it goes from this directly to [itex]ln (x+\sqrt{x^{2}+y^{2}})[/itex], a result wolframalpha says is valid for 'restricted [itex]x[/itex] values'. What does it mean? What are those restricted values? Why?

Many thanks.



Well, since this is indefinite integration both the results are correct as their difference is just the constant [itex]-\ln d[/itex].

The question is: where did you get the constant [itex]d[/itex] from??

The result is valid for any values of [itex]x,y, s.t. x^2+y^2\neq 0[/itex]

DonAntonio
 
Thank you. 'd' is actually a constant length (the distance from a point p to a disk, in an axis that goes through the center of the disk)
 

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