What Are the Two Angles for a Fire Hose to Reach 2.0 Meters?

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SUMMARY

The discussion focuses on determining the angles required for a fire hose to project water 2.0 meters away, given a launch speed of 6.8 m/s. The relevant equations include the time of flight formula, t = 2 * 6.8 * sin(angle) / 9.81, and the horizontal distance formula, dx = vix * t. The presence of two angles arises from the physics of projectile motion, where both a low and a high angle can achieve the same horizontal distance. The user seeks clarification on how to solve for these angles using the provided equations.

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  • Knowledge of basic physics equations for motion
  • Ability to manipulate algebraic equations
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Homework Statement


A fire hose held near the ground shoots water at a speed of 6.8 m/s. At what angle(s) should the nozzle point in order that the water land 2.0 m away? Why are there two different angles?

The Attempt at a Solution


First, I don't know why there would be two angles. I only found the formula, but I don't know how to solve the angle out. I found t=2* 6.8sinangle/9.81(I don't know how to use the angle symbol) dx=vix*t, 2=6.8cosangle*2*6.8sinangle/9.81. How to find the angle?

Thank you.
 
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I found t=2* 6.8sin(angle)/ 9.81. dx=vix*t, 2=6.8cos(angle)*2*6.8sin(angle)/9.81. How to find the angle? I rewrite it because I just want to make sure you understand what I am talking about. Really hope someone can help me! thanks.
 

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