What are the units for Ksp and why are they not always included in calculations?

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SUMMARY

The solubility product constant (Ksp) for calcium hydroxide is experimentally determined to be 3.0 x 10^-7. While calculations suggest that Ksp should have units of M^3, it is established that Ksp is dimensionless. This is due to the nature of equilibrium constants, which must be dimensionless as they relate to the Gibbs free energy equation (ΔGo = -RTlnK). The concentrations in the Ksp expression are normalized to a standard state of 1M, allowing for a dimensionless representation.

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Homework Statement


I have found, through experimentation, the ksp of calcium hydroxide to be 3.0 x10^-7 (which i know has a pretty large percent error). However, i am conflicted as to what the units should be because logically, plugging the units into the ksp equation should give you units of M^3 (ksp= [ca][oh-]^2. However, after research online, i found that ksp doesn't have units. Why does Ksp have no units if it is seemingly so easy to calulate it?

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The Attempt at a Solution


One idea i was thinking about was that the ksp units are unique to each equation which may be why they are omitted?
 
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The units for the solubility product should indeed be M3. I have not found that "Ksp doesn't have units" online. However, insofar as a solubility product is an equilibrium constant, strictly speaking equilibrium constants should be dimensionless, as ΔGo = -RTlnK, and the argument of a logarithm must be dimensionless. This is achieved by dividing each concentration by the concentration of the standard state, i.e. 1M. So
Ksp = ([Ca2+]/1M)([OH-]/1M)2
which has numerically the same value as your Ksp.
However, I like to keep the units, as it's a useful check on whether you're getting the powers right.
 

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