What are the Vector Components for a Plane's Emergency Landing in Galisto?

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SUMMARY

The discussion focuses on calculating the vector components for a plane's emergency landing in Galisto after it flies 180 km at 68.0 degrees east of north and then 260 km at 48.0 degrees south of east. Participants emphasize the need to break down the journey into North-South and East-West components using trigonometric equations. The solution involves adding these components separately to determine the overall position of the plane at the time of landing.

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Homework Statement


A plane leaves the airport in Galisto and flies 180 km at 68.0 (degrees) east of north and then changes direction to fly 260 km at 48.0 (degrees) south of east, after which it makes an immediate emergency landing in a pasture.


Homework Equations


Trig equations?


The Attempt at a Solution


Well I tried to use trigonometry to find any of the angles, but where I get stuck is, I only know the 2 given sides, that's about it.
 
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SaltyBriefs said:

Homework Statement


A plane leaves the airport in Galisto and flies 180 km at 68.0 (degrees) east of north and then changes direction to fly 260 km at 48.0 (degrees) south of east, after which it makes an immediate emergency landing in a pasture.


Homework Equations


Trig equations?


The Attempt at a Solution


Well I tried to use trigonometry to find any of the angles, but where I get stuck is, I only know the 2 given sides, that's about it.

The first part of the trip will have a North-South Component [going North] and an East-West component [going East]
The second part will had a North-South Component [going South] and an East-West Component [going East]
Add the components separately [who knows, the North-South Components might actually cancel out] to get two over-all components from which you can locate the plane.
 

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