What Calculations Are Needed to Convert Steam to Water and Ice to Steam?

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SUMMARY

The discussion focuses on calculating the heat transfer involved in phase changes of water, specifically converting steam to water and ice to steam. The calculations provided include removing -985,000 J of heat from 400 grams of steam at 200 degrees Celsius to convert it to water at 100 degrees Celsius and absorbing 3,100,000 J of heat to convert 1 kg of ice at -20 degrees Celsius to steam at 130 degrees Celsius. Key formulas involve the specific heat capacity and latent heat of vaporization, emphasizing the importance of phase changes in energy calculations.

PREREQUISITES
  • Understanding of specific heat capacity
  • Knowledge of latent heat of vaporization
  • Familiarity with phase change concepts
  • Basic algebra for heat transfer calculations
NEXT STEPS
  • Study the specific heat capacity of water and ice
  • Learn about the latent heat of fusion and vaporization
  • Explore thermodynamic principles related to phase changes
  • Practice heat transfer calculations with different substances
USEFUL FOR

Students studying thermodynamics, educators teaching heat transfer concepts, and anyone interested in the physics of phase changes in water.

xxiangel
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Temperature Problems... Confused! please help!

How much heat must be taken away from 400 grams of steam at 200 degrees to change it into water at 100 degrees? (Teacher says answer is -985,000 J)

How much heat must be absorbed by 1 kg of ice at -20 degrees celsius to change it to steam at 130 degrees? (Answer is 3,100,000 J)


If someone could please show me how to work out these problems, it would be wonderful! Thank you so much! :smile:
 
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xxiangel said:
How much heat must be taken away from 400 grams of steam at 200 degrees to change it into water at 100 degrees? (Teacher says answer is -985,000 J)
How many moles of H2O in 400 g. of steam? What heat is given off in cooling to 100 deg. C? What is the heat removed from water turning from vapour to liquid?

How much heat must be absorbed by 1 kg of ice at -20 degrees celsius to change it to steam at 130 degrees? (Answer is 3,100,000 J)
Use the same approach as above.

AM
 
its very very easy...

what andrew said is right...but i will explain it to u...
when steam is to be converted into water it has to lose heat...but one important thing u have to notice is that...when a substance is changing its phase its losing more heat than when a small temperature change occurs...
first let's take steam from 200 to equilibrium..ie 100 degrees...for that heat required is equal to...Q=.4*c*(373-473)...now,steam has to spend some energy to convert steam into water...for that Q1=L*.4...where L is the latent heat of vapourization...then add Q & Q1...remember the added value will be negative as the heat energy is lost here and not gained...remember to convert grams into kilograms for getting answer in SI units...do the same for the second question as well...here Q maybe positive as here we need more energy to convert a solid to vapour...

finally just remember this...we need a lot of energy to change the phase of a substance...and always calculate Q by dividing it into various Qs wherever a phase change is taking place...ok yaaaaaar
 
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