What Causes the Net Torque on a Uniform Disk?

Click For Summary

Homework Help Overview

The discussion revolves around calculating the net torque on a uniform disk subjected to two forces. The disk has specific mass and radius values and is free to rotate about a frictionless axle.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the torque formula and the directionality of torque. There is an exploration of the correctness of the calculated torque value and its sign based on convention.

Discussion Status

Some participants have provided guidance regarding the interpretation of torque signs and have confirmed the calculations based on the given information. There is an ongoing exploration of the implications of the sign of the torque.

Contextual Notes

Participants are operating under the assumption that the provided information is accurate, and there is a mention of differing conventions regarding torque direction in their physics texts.

whitesox
Messages
2
Reaction score
0
[SOLVED] Net torque of uniform disk

Homework Statement


A uniform disk with a mass of 34.8 kg and a radius of 0.32 m is free to rotate about a frictionless axle. Forces of 90.0 N and 125 N are applied to the disk, as the drawing indicates.

What is the net torque produced by the two forces?

Homework Equations


Torque = rFsin(theta)

The Attempt at a Solution


I've tried using the equation above...125(0.32)sin90 - 90(0.32)sin90 = 11.2 N*m which is wrong. I know this question is trivial, but I'm pretty frustrated at this point...any help would be great.
 
Last edited:
Physics news on Phys.org
Assuming the information given is correct, I agree with you that the magnitude of the torque is 11.2 Nm. My physics text usually considered counterclockwise as positive, with clockwise as the negative direction, so I actually got -11.2Nm. This isn't the problem right? If not I would check that you have the correct information.
 
G01 said:
Assuming the information given is correct, I agree with you that the magnitude of the torque is 11.2 Nm. My physics text usually considered counterclockwise as positive, with clockwise as the negative direction, so I actually got -11.2Nm. This isn't the problem right? If not I would check that you have the correct information.

It's the correct information, and the answer is -11.2. Thanks.
 
Anytime!
 


What is the magnitude of the angular acceleration of the disk?
 

Similar threads

Replies
6
Views
3K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 10 ·
Replies
10
Views
6K
Replies
5
Views
1K
  • · Replies 7 ·
Replies
7
Views
20K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
8K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K