What Current Corresponds to a 16 Ohm, 0.1 W Speaker?

  • Thread starter Thread starter jakeowens
  • Start date Start date
  • Tags Tags
    Current Resistors
Click For Summary
SUMMARY

The current corresponding to a 16 Ohm, 0.1 W speaker can be calculated using the formula P = I^2 R. Given that the power (P) is 0.1 W and the impedance (R) is 16 Ohms, the current (I) can be determined as I = √(P/R), resulting in approximately 0.25 A. It is crucial to note that the 16 Ohm rating refers to the speaker's impedance at a specific audio frequency, not its DC resistance, which is typically lower. Calculations should utilize RMS values for voltage and current.

PREREQUISITES
  • Understanding of Ohm's Law (V = IR)
  • Familiarity with power formulas (P = IV, P = I^2 R)
  • Knowledge of AC vs. DC circuits
  • Basic concepts of speaker impedance
NEXT STEPS
  • Research speaker impedance and its impact on audio performance
  • Learn about RMS values in AC circuits
  • Explore the relationship between voltage, current, and power in audio systems
  • Investigate the differences between DC resistance and AC impedance in speakers
USEFUL FOR

Electronics enthusiasts, audio engineers, and anyone involved in designing or troubleshooting audio equipment will benefit from this discussion.

jakeowens
Messages
34
Reaction score
0
The little speaker in a portable radio is labeled 16 Ohm's , 0.1 W. To what current does that correspond?


I'm kind of confused where to go with this one. what i know is this, 1 watt=1volt*1amp, but where do i go from there?

Do I have to use Ohm's law somehow? V=IR.

So does VI=.1 and R=16 ohms? am i supposed to be able to solve for I from that or something?

im just confused as to where to go next with this problem. This is the first problem I've had with Watts.

Thanks for any tips.
 
Physics news on Phys.org
if you know V=IR and that P=IV

then you know that P=I^2 R
 
Actually, it's a little more complicated than Andrew's hints. You are asking about an audio speaker, and the DC resistance is not the 16 Ohm number. Its DC resistance is likely very low, since it's just a coil of wire around a magnet.

The 16 Ohm number is the impedance at some audio frequency. I didn't know what frequency is used for the standard, so I googled the following:

16 ohm speaker impedance resistance

and got a lot of useful hits. Here is a very good tutorial on speaker impedance:

http://www.epanorama.net/documents/audio/speaker_impedance.html

From that article it looks like the DC resistance isn't super-low as I'd assumed, but it is still less than the quoted AC impedance, like the 16 Ohms of your problem. So I guess that Andrew's hints are still valid, but just keep in mind that the I and V that you are using in your calculations are RMS values, not DC or peak or peak-to-peak.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
3K
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
1K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 20 ·
Replies
20
Views
16K
  • · Replies 5 ·
Replies
5
Views
7K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K