What Determines the Sign of Lambda in Separation of Variables?

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The sign of lambda in the separation of variables approach significantly affects the solvability of differential equations. When lambda is positive, the solutions yield real exponential functions, which often cannot satisfy certain boundary conditions. In contrast, a negative lambda leads to periodic solutions, such as sine and cosine functions, that can meet these conditions. The choice of lambda's sign should be guided by whether the X or Y function will provide the necessary eigenvalues for the problem. Ultimately, the selection depends on the specific boundary or initial conditions being applied.
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Just quick question about sep of variables..

say have function U(x,y)=X(x)Y(y)

when do separation of variables end up with some generic case that looks like:

X''/X=Y'/Y=lamda

my question is (and I think I know now the answer but would like confirmation), is what sign should the lamda be set to to make the problem easiest to solve...

And I think that it is down to which of the two, either X or Y that are going to give us the eigenvalues...
if X gives eigen values, then set lamda to the sign that allows the X differential equation easiest to solve and vise versa if Y ODE gives eigenvalues...

I'm just looking for a rule of thumb here or any tips anyone has..Thanks
 
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The sign of \lambda usually depends on initial or boundary conditions. For example, we can consider solutions to

\frac{X''}{X} = \lambda.

When \lambda>0, our solutions are real exponential functions e^{\pm\sqrt{\lambda} x. It is impossible to satisfy the boundary conditions X(0)=X(a)=0 with a linear combination of these solutions.

However, if \lambda<0, we find periodic solutions e^{\pm i\sqrt{\lambda} x (equivalent to sin and cos) for which there is a linear combination that satisfies X(0)=X(a)=0.

Therefore, you will generally need to consider the full range of parameters and decide which classes of solutions are permissible given the boundary or initial conditions.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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