What Do the Elements of $\mathbb{Z}_2 \times \mathbb{Z}$ Look Like?

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SUMMARY

The discussion focuses on the additive group $\mathbb{Z}_2 \times \mathbb{Z}$, specifically examining the elements of this group and their orders. It establishes that elements are of the form $(x,y)$ where $x \in \mathbb{Z}_2$ and $y \in \mathbb{Z}$. The participants confirm that for the elements $A = (1,k)$ and $B = (0,-k)$, both have infinite order while their sum $A + B = (1,0)$ has a finite order of 2. This conclusion is verified as correct by the participants.

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  • Understanding of group theory concepts, specifically additive groups.
  • Familiarity with the structure of $\mathbb{Z}_2$ and $\mathbb{Z}$.
  • Knowledge of element orders in group theory.
  • Basic algebraic manipulation of ordered pairs.
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  • Study the properties of direct products of groups, particularly $\mathbb{Z}_2 \times \mathbb{Z}$.
  • Explore the concept of infinite and finite order elements in group theory.
  • Learn about other examples of groups with mixed finite and infinite order elements.
  • Investigate the implications of element orders on group structure and behavior.
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Mathematicians, students of abstract algebra, and anyone interested in the properties of group theory and additive groups.

mathmari
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Hey! :o

To show that in the additive group $\mathbb{Z}_2\times\mathbb{Z}$ there are non-zero elements $A,B$ of infinite order such that $A+B$ has finite order, we have to find such $A$ and $B$, right? (Wondering)

How do the elements of $\mathbb{Z}_2\times\mathbb{Z}$ look like? (Wondering)
 
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The elements of $\mathbb{Z}_2\times\mathbb{Z}$ are of the form $(x,y)$ where $x\in \mathbb{Z}_2$ and $y\in \mathbb{Z}$, right? (Wondering)

And the order of such an element is $n$ for which $(nx,ny)=(0,0)$, right?

For $A=(1,k)$ and $B=(0,-k)$ for $k\in \mathbb{Z}_{>0}$, we have that $A+B=(1,0)$, right?

$A$ and $B$ have infinite order, since the second coordinate is never equal to $0$ for $k>0$, and $A+B$ has finite order, and specifically the order is $2$, since $2(1,0)=(2,0)=(0,0)$.

Is this correct? (Wondering)
 
Yep. All correct. (Happy)
 
Great! Thank you! (Sun)
 

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