What Do the Elements of $\mathbb{Z}_2 \times \mathbb{Z}$ Look Like?

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Discussion Overview

The discussion centers around the structure of the additive group $\mathbb{Z}_2 \times \mathbb{Z}$, specifically exploring the nature of its elements and their orders. Participants examine the existence of non-zero elements of infinite order that combine to yield an element of finite order.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant inquires about the elements of $\mathbb{Z}_2 \times \mathbb{Z}$ and their representation.
  • Another participant states that elements take the form $(x,y)$ where $x \in \mathbb{Z}_2$ and $y \in \mathbb{Z}$, and proposes a method to determine the order of such elements.
  • A specific example is provided with $A=(1,k)$ and $B=(0,-k)$ for $k \in \mathbb{Z}_{>0}$, suggesting that both $A$ and $B$ have infinite order while their sum $A+B=(1,0)$ has finite order, specifically 2.
  • One participant confirms the correctness of the previous claims.

Areas of Agreement / Disagreement

Participants generally agree on the correctness of the claims made regarding the elements and their orders, with no significant disagreement noted.

Contextual Notes

The discussion does not address potential limitations or assumptions regarding the definitions of order or the specific elements chosen.

mathmari
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Hey! :o

To show that in the additive group $\mathbb{Z}_2\times\mathbb{Z}$ there are non-zero elements $A,B$ of infinite order such that $A+B$ has finite order, we have to find such $A$ and $B$, right? (Wondering)

How do the elements of $\mathbb{Z}_2\times\mathbb{Z}$ look like? (Wondering)
 
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The elements of $\mathbb{Z}_2\times\mathbb{Z}$ are of the form $(x,y)$ where $x\in \mathbb{Z}_2$ and $y\in \mathbb{Z}$, right? (Wondering)

And the order of such an element is $n$ for which $(nx,ny)=(0,0)$, right?

For $A=(1,k)$ and $B=(0,-k)$ for $k\in \mathbb{Z}_{>0}$, we have that $A+B=(1,0)$, right?

$A$ and $B$ have infinite order, since the second coordinate is never equal to $0$ for $k>0$, and $A+B$ has finite order, and specifically the order is $2$, since $2(1,0)=(2,0)=(0,0)$.

Is this correct? (Wondering)
 
Yep. All correct. (Happy)
 
Great! Thank you! (Sun)
 

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