What do the subscripts in the gradient notation represent?

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Discussion Overview

The discussion revolves around the notation used in gradient expressions related to forces acting on point masses in a system. Participants explore the meaning of subscripts in the gradient notation, particularly ##\nabla_i## and ##\nabla_{\vec{r_k}}##, and how these relate to the potential energy in systems with multiple interacting particles.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions the meaning of the subscript ##i## in the gradient notation ##\nabla_i##, seeking clarification on its significance.
  • Another participant asserts that the force on particle ##i## is equal to the gradient of the potential with respect to the coordinates of that particle.
  • A different participant suggests that the expression should be written as ##\vec{F_i} = \nabla V(\vec{r_i})##, implying a potential correction to the notation.
  • In response, a participant explains that the minus sign in the force equation is conventional, relating it to how potential energy decreases when work is done by the force.
  • Further, a participant clarifies that the potential is a function of all positions, necessitating the specification of which position the gradient is taken with respect to, especially in systems with interactions between particles.
  • This participant also introduces the concept of external potentials and how they differ from the total potential, indicating that the situation is more complex than considering isolated particles.

Areas of Agreement / Disagreement

Participants express differing views on the notation and its implications, with some agreeing on the conventional use of the minus sign while others debate the correct form of the force expression. The discussion remains unresolved regarding the notation and its interpretation.

Contextual Notes

There are limitations in the assumptions made about the interactions between particles and the nature of the potential energy, which are not fully explored in the discussion.

Nikitin
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Hi!

Two exerts from my lecture notes:

"Assume we have a system of point masses in position ##\vec{r_i}## which are influenced by forces ##\vec{F_i}##."

"Let's say you have a system where ##\vec{F_i} = - \nabla_i V##"

In the second line, what does the notation ##\nabla_i## mean? Why is that sub ##i## there?

They use similar notation in here "##\nabla_{\vec{r_k}}##" http://en.wikipedia.org/wiki/Virial_theorem#Connection_with_the_potential_energy_between_particles

What does the r_k mean?
 
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The force on particle ##i## is equal to the gradient of the potential with respect to the coordinates of particle ##i##.
 
Orodruin said:
The force on particle ##i## is equal to the gradient of the potential with respect to the coordinates of particle ##i##.
Shouldn't it instead be ##\vec{F_i} = \nabla V(\vec{r_i})## ?
 
No. The minus sign is conventional so that you decrease the potential when the force does work. Compare with gravitational potential in a homogeneous field. It increases with height and so has positive z derivative, yet the force points down.
 
Oh I forgot to add the minus sign. never mind that. What I was asking about were the indexes.
 
No, the potential is a function that involve all positions, which is why you need to specify which position you take the gradient with respect to. For example, if you have two charged particles, the potential will be a function of the distance between them, which is a function of both positions.

I think you are imagining the case when all of the particles move in an external potential with no inter-particle interactions. Then it will be possible to divide the potential into several contributions V(r1,r2,...) = U(r1) + U(r2) + ... Note that I here introduced the external potential U, which is a priori a different function than V - the total potential. Inserting this into the expression you were asking about will give you something like what you quoted, but as I said, this is not the general situation with interactions within the system.
 
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OK, I see. Thank you!
 

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