What does [A,1] equal in a commutator?

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binbagsss
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Homework Statement
below
Relevant Equations
below
I'm just trying to follow the below
expop.png

And I understand all, I think, except what's happened to the term when A hits 1: [A,1] ?
If I'm correct basically we're just hitting on the first operator so reducing the power by one each time of the operator in the right hand bracket

thanks
 

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If I understand this correctly, ##1## is the identity operator. So what would be the value of ##[A,1]##?
 
[A,1]=0 since 1 is pure number!
 
Abhishek11235 said:
[A,1]=0 since 1 is pure number!
omg i think i need some sleeep ! thank you haha :)
 
binbagsss said:
omg i think i need some sleeep ! thank you haha :)
A typo! 1 here refers to identity operator as @tnich says. Anyways,final result is same