From an inertial reference frame S, the vector position of a particle of mass
m1 = 1kg is given by r1(t)=(tx-hat - t^2y-hat)m.
The vector position of a particle m2=2m1 is given by r2=(t)=(tx-hat +t^3y-hat)m
Is particle #1 free along the y-direction? Explain
If the particle is free along the y-direction then the y's would equal to 0.
The Attempt at a Solution
(I am actually unsure if my definition of free is true)