What does the notation ln^2 mean in logarithm notation?

  • Thread starter Thread starter Feodalherren
  • Start date Start date
  • Tags Tags
    Logarithm Notation
Click For Summary

Homework Help Overview

The discussion revolves around the interpretation of logarithmic notation, specifically the meaning of the notation ln² in the context of an equation involving ln(1+x).

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the notation ln² and questions whether it could mean (Log(e))². Other participants clarify that it represents (ln(1+x))²=4, leading to further exploration of the implications of this notation.

Discussion Status

Participants are actively clarifying the meaning of the notation and its implications for the equation. Some have provided insights into the general notation of functions, while others are confirming the interpretation of the original poster's equation.

Contextual Notes

There is an underlying assumption that the notation ln² is not commonly used, leading to confusion. The discussion also touches on the general rules of function notation, which may not be universally understood.

Feodalherren
Messages
604
Reaction score
6

Homework Statement


\left(ln\stackrel{2}{}(1+x)=4\right)

I've never seen a number above the ln like that, usually it's on another term or simply ln(2). What does that numer mean? Is it Log(e)^2 i.e. (Loge)(Loge)? That doesn't make any sense to me.

Homework Equations


-


The Attempt at a Solution



Bring the 2 down and divide both sides by it.
ln (1+x)=2

(e^2) - 1=x

It's supposed to have one more solution, x = (1/(e^2)) - 1
 
Physics news on Phys.org
It means

(ln(1+x))^2=4
 
Ah that makes complete sense. Thank you.
 
Remember that for, any function, f, the notation "f(x)" means the function evaluated at x- that is, f(x) is a number and so f^n(x) is that number to the nth power. Generally, for any function, f, the notation fn means "the value of f to the nth power".

The only (unfortunate) exception to that is '-1'. f^{-1} typically means "the inverse function", not 1/f.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
12
Views
2K
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K